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A body is projected in vertical direction. The altitude y is given by y=10t2-9t 5. Calculate the initial velocity of the body?
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A body is projected in vertical direction. The altitude y is given by ...
Calculating the Initial Velocity of a Projected Body:
1. Given Equation:
The altitude of the body is given by the equation y = 10t^2 - 9t 5, where y represents the altitude at time t.
2. Initial Velocity:
The initial velocity of the body can be calculated by finding the derivative of the altitude equation with respect to time. The derivative of the altitude equation gives us the velocity of the body at any given time.
3. Derivative of Altitude Equation:
Taking the derivative of y = 10t^2 - 9t gives us the velocity equation v = 20t - 9.
4. Initial Velocity:
To find the initial velocity, we need to evaluate the velocity equation at time t = 0, as the initial velocity is the velocity of the body at the initial moment of projection.
5. Calculating Initial Velocity:
Substitute t = 0 into the velocity equation v = 20t - 9:
v = 20(0) - 9
v = -9 m/s
6. Conclusion:
Therefore, the initial velocity of the body projected in the vertical direction is -9 m/s. This negative sign indicates that the body is projected downwards.
By following these steps and calculations, you can determine the initial velocity of a body projected vertically using its altitude equation.
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A body is projected in vertical direction. The altitude y is given by ...
9t ke baad 5 kya hai??
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A body is projected in vertical direction. The altitude y is given by y=10t2-9t 5. Calculate the initial velocity of the body?
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