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There is a thin plate AbCD with an optical hole as shown in figure the coefficient of linear expansion of the sheet is alpha when the temperature of the plate is increased by temperature TK the area of the hole increase by an amount ?
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There is a thin plate AbCD with an optical hole as shown in figure the...
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Introduction:

The problem describes a thin plate AbCD with an optical hole. The coefficient of linear expansion of the sheet is alpha. The problem requires us to find out the amount by which the area of the hole increases when the temperature of the plate is increased by temperature TK.

Solution:

When the temperature of a material increases, it expands due to the increase in thermal energy. The amount of expansion is given by the coefficient of linear expansion (alpha) and the change in temperature (TK).

The change in area of the hole can be calculated by considering it as a rectangle with sides parallel to the edges of the plate. Let the length and breadth of the rectangle be l and b respectively. Then the change in length and breadth are given by:

Change in length = alpha * l * TK

Change in breadth = alpha * b * TK

The change in area of the rectangle is given by:

Change in area = l * b * alpha * TK + b * alpha * l * TK

= 2 * l * b * alpha * TK

Therefore, the change in area of the hole is 2 times the product of the length and breadth of the rectangle and the coefficient of linear expansion and the change in temperature.

Conclusion:

Thus, the area of the hole increases by 2 times the product of the length and breadth of the rectangle and the coefficient of linear expansion and the change in temperature.
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There is a thin plate AbCD with an optical hole as shown in figure the coefficient of linear expansion of the sheet is alpha when the temperature of the plate is increased by temperature TK the area of the hole increase by an amount ?
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