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A body is projected with an initial velocity 20√2 m/s at an angle of 45� with the horizontal then find maximum height, time of ascent and range.?
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Given
- Initial velocity = 20√2 m/s
- Angle of projection = 45° with horizontal
Maximum Height
To find the maximum height, we need to use the formula:
Maximum Height = (u²sin²θ) / 2g
where, u is the initial velocity, θ is the angle of projection and g is the acceleration due to gravity.
Substituting the given values, we get:
Maximum Height = (20√2)²sin²45° / 2 * 9.8
Maximum Height = 204.08 meters
Therefore, the maximum height reached by the body is 204.08 meters.
Time of Ascent
To find the time of ascent, we need to use the formula:
Time of Ascent = u * sinθ / g
Substituting the given values, we get:
Time of Ascent = 20√2 * sin45° / 9.8
Time of Ascent = 2 seconds
Therefore, the time taken by the body to reach the maximum height is 2 seconds.
Range
To find the range, we need to use the formula:
Range = u²sin2θ / g
Substituting the given values, we get:
Range = (20√2)²sin2(45°) / 9.8
Range = 408.16 meters
Therefore, the range of the body is 408.16 meters.
Conclusion
In conclusion, the maximum height reached by the body is 204.08 meters, the time taken by the body to reach the maximum height is 2 seconds and the range of the body is 408.16 meters.
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A body is projected with an initial velocity 20√2 m/s at an angle of 45� with the horizontal then find maximum height, time of ascent and range.?
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A body is projected with an initial velocity 20√2 m/s at an angle of 45� with the horizontal then find maximum height, time of ascent and range.? for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about A body is projected with an initial velocity 20√2 m/s at an angle of 45� with the horizontal then find maximum height, time of ascent and range.? covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A body is projected with an initial velocity 20√2 m/s at an angle of 45� with the horizontal then find maximum height, time of ascent and range.?.
A body is projected with an initial velocity 20√2 m/s at an angle of 45� with the horizontal then find maximum height, time of ascent and range.? for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about A body is projected with an initial velocity 20√2 m/s at an angle of 45� with the horizontal then find maximum height, time of ascent and range.? covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A body is projected with an initial velocity 20√2 m/s at an angle of 45� with the horizontal then find maximum height, time of ascent and range.?.
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