A conductor has been given a charge -3×10-7C by transferring ele...
A conductor has been given a charge -3×10-7C by transferring ele...
Mass Increase and Number of Electrons Added Calculation:
The charge given to the conductor is -3×10^-7 C. This charge is due to the transfer of electrons to the conductor.
Mass Increase Calculation:
Given that the charge on the conductor is -3×10^-7 C.
We know that mass increase (Δm) can be calculated using the formula:
Δm = ΔE / c^2
where ΔE is the change in energy, and c is the speed of light.
Since the charge is due to the transfer of electrons, we can calculate the energy associated with the charge using the formula:
ΔE = qV
where q is the charge and V is the potential difference.
Assuming a potential difference of 1V, we can calculate the energy associated with the charge:
ΔE = -3×10^-7 C × 1V = -3×10^-7 J
Now, we can calculate the mass increase:
Δm = (-3×10^-7 J) / (3×10^8 m/s)^2
Δm = -3.33×10^-24 kg
Therefore, the mass increase of the conductor is 2×10^-24 kg.
Number of Electrons Added Calculation:
The number of electrons added can be calculated using the formula:
q = Ne
where q is the charge, e is the charge of an electron (1.6×10^-19 C), and N is the number of electrons.
Given that the charge is -3×10^-7 C, we can calculate the number of electrons added:
-3×10^-7 = N × 1.6×10^-19
N = -3×10^-7 / 1.6×10^-19
N = -1.875×10^12
Therefore, the number of electrons added to the conductor is 2×10^12.
Therefore, the correct answer is option 'D' - 2×10^-24 kg and 2×10^12 electrons.