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Two unit negative charges are placed on a straight line. A positive charge q is placed exactly at the mid-point between these unit charges. If the system of these three charges is in equilibrium, the value of q (in C) is
  • a)
    1.0
  • b)
    0.75
  • c)
    0.5
  • d)
    0.25
Correct answer is option 'D'. Can you explain this answer?
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Two unit negative charges are placed on a straight line. A positive ch...
For equilibrium, we have


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Two unit negative charges are placed on a straight line. A positive ch...
Given:
- Two unit negative charges are placed on a straight line.
- A positive charge q is placed exactly at the midpoint between these unit charges.
- The system of these three charges is in equilibrium.

To find:
- The value of q (in C)

Explanation:
1. Understanding the problem:
- In this problem, we have a system of three charges: two unit negative charges and one positive charge.
- The charges are placed in a straight line, with the positive charge at the midpoint between the negative charges.
- The system is in equilibrium, which means that the forces acting on each charge cancel out, resulting in no net force.

2. Equilibrium condition:
- For a system of charges to be in equilibrium, the net force on each charge must be zero.
- The net force on a charge is the vector sum of the forces exerted on it by the other charges.
- In this case, the positive charge experiences a repulsive force from each of the negative charges.
- The magnitudes of these forces are given by Coulomb's law: F = k * q1 * q2 / r^2, where k is the electrostatic constant, q1 and q2 are the charges, and r is the distance between them.
- As the system is in equilibrium, the magnitudes of the two repulsive forces acting on the positive charge must be equal.

3. Analyzing the forces:
- Let's assume the distance between the positive charge and each negative charge is d.
- The magnitude of the force between a negative charge and the positive charge is F1 = k * (-1) * q / d^2.
- The magnitude of the force between the other negative charge and the positive charge is F2 = k * (-1) * q / d^2.
- Since the forces must be equal in magnitude, we have F1 = F2, which leads to (-1) * q / d^2 = (-1) * q / d^2.

4. Solving for q:
- Simplifying the equation, we get q / d^2 = q / d^2.
- Cross-multiplying, we have q * d^2 = q * d^2.
- Dividing both sides by q, we get d^2 = d^2.
- Taking the square root of both sides, we have d = d.
- The distance between the positive charge and each negative charge is the same, so d = d/2 + d/2 = d.
- Therefore, the distance between the positive charge and each negative charge is equal to the distance between the negative charges.
- Since the negative charges are unit charges, the distance between them is 1 unit.
- Therefore, the distance between the positive charge and each negative charge is 1 unit.

5. Calculating q:
- Using the distance d = 1 unit, we can find the value of q.
- Using Coulomb's law, we have F = k * q1 * q2 / r^2.
- Plugging in the values, we have F = k * (-1) * 1 * 1 / 1^2 = -k.
- As the forces must be equal, we have -k = -k.
- Therefore
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Two unit negative charges are placed on a straight line. A positive charge q is placed exactly at the mid-point between these unit charges. If the system of these three charges is in equilibrium, the value of q (in C) isa)1.0b)0.75c)0.5d)0.25Correct answer is option 'D'. Can you explain this answer?
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Two unit negative charges are placed on a straight line. A positive charge q is placed exactly at the mid-point between these unit charges. If the system of these three charges is in equilibrium, the value of q (in C) isa)1.0b)0.75c)0.5d)0.25Correct answer is option 'D'. Can you explain this answer? for Class 12 2024 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about Two unit negative charges are placed on a straight line. A positive charge q is placed exactly at the mid-point between these unit charges. If the system of these three charges is in equilibrium, the value of q (in C) isa)1.0b)0.75c)0.5d)0.25Correct answer is option 'D'. Can you explain this answer? covers all topics & solutions for Class 12 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Two unit negative charges are placed on a straight line. A positive charge q is placed exactly at the mid-point between these unit charges. If the system of these three charges is in equilibrium, the value of q (in C) isa)1.0b)0.75c)0.5d)0.25Correct answer is option 'D'. Can you explain this answer?.
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