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A wire whose resistance 0.1/cm is bent in the form of a square ABCD of side 10 cm. An exactly similar wire is connect across the points B and D. What will be the equivalent resistance between the other two corners A and C of the square?If a 2V battery be connected between A and C,then what will be the current drawn from the battery? If an ammeter be connected B and D,what will it read?
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A wire whose resistance 0.1/cm is bent in the form of a square ABCD of...
**Equivalent Resistance between A and C:**

To find the equivalent resistance between points A and C, we can use the concept of resistors in parallel and series.

1. **Resistors in parallel:** The wires connected between points B and D are in parallel with the wire between points A and C. Since the wires are exactly similar, they have the same resistance of 0.1 Ω/cm.

2. **Resistors in series:** The wire between points B and D is in series with the wire between points A and C. The total length of the wire for both sections is 20 cm (10 cm for each section).

3. **Finding the equivalent resistance:** To find the equivalent resistance, we need to calculate the resistance of each section separately and then combine them.

a. Resistance of the wire between B and D: Since the total length of the wire is 10 cm, the resistance is given by R = ρ * (L/A) = 0.1 Ω/cm * (10 cm / 1 cm^2) = 1 Ω.

b. Resistance of the wire between A and C: Again, the total length of the wire is 10 cm, so the resistance is also 1 Ω.

c. Combining the resistances: The resistors are in series, so we add them up. The equivalent resistance is R_eq = R1 + R2 = 1 Ω + 1 Ω = 2 Ω.

**Current Drawn from the Battery:**

To find the current drawn from the battery, we can use Ohm's Law, which states that the current (I) flowing through a conductor is equal to the voltage (V) across the conductor divided by its resistance (R).

1. **Applying Ohm's Law:** We have a 2V battery connected between points A and C, and the equivalent resistance between these points is 2 Ω. Therefore, the current drawn from the battery is given by I = V / R = 2V / 2 Ω = 1A.

**Ammeter Reading between B and D:**

The ammeter connected between points B and D will measure the current flowing through that section of the wire.

1. **Calculating the current:** Since the wire between B and D has a resistance of 1 Ω, and there is a 2V potential difference across it (due to the battery), we can again use Ohm's Law to calculate the current. I = V / R = 2V / 1 Ω = 2A.

2. **Ammeter reading:** Therefore, the ammeter connected between B and D will read a current of 2A.

In summary, the equivalent resistance between points A and C is 2 Ω, the current drawn from the battery connected between A and C is 1A, and the ammeter connected between B and D will read a current of 2A.
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A wire whose resistance 0.1/cm is bent in the form of a square ABCD of...
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Read the following text and answer the following questions on the basis of the same:Shunt resistance: The ammeter shunt is the device which provides the low resistance path to the flow of current. It is connected in parallel with the ammeter. In some ammeter the shunt is in-built inside the instrument while in others it is externally connected to the circuit. Ammeters are designed for measurement of low current. For measuring high current, the shunt is connected in parallel to the ammeter. The significant portion of the current passes to the shunt because of the low resistance path and little amount of current passes through the ammeter. The shunt is connected in parallel to the ammeter because of which the voltage drops across the meter and shunt remain the same. Thus, the movement of the pointer is not affected by the shunt. Let us consider that the current to be measured is I. The circuit has ammeter and shunt connected parallel to each other. The ammeter is designed for measurement of small current say, Im. The magnitude of the current I passes through the meter is very high, and it will burn the meter. So, for measuring the current I the shunt is required in the circuit. As the shunt connects in parallel with the ammeter, thus the same voltage drops occur between them:IShRSH = ImRm∴ RSH = ImRm/ISHShunt current ISH = I – ImSo, RSH = ImRm/(I – Im)∴ I/Im = 1 + (Rm/RSH)The ratio of the total current to the current required for the movement of the ammeter coil is called the multiplying power of the shunt.∴ The multiplying power = m = I/ImRSH = Rm / (m – 1)The following are the requirements of the shunt.• The resistance of the shunt should remain constant with time.• The temperature of the material should remain the same even though substantial current flows through the circuit.What will be the value of the shunt resistance if the ammeter coil resistance is 1Ω and multiplying power is 100?

Read the following text and answer the following questions on the basis of the same:Shunt resistance: The ammeter shunt is the device which provides the low resistance path to the flow of current. It is connected in parallel with the ammeter. In some ammeter the shunt is in-built inside the instrument while in others it is externally connected to the circuit. Ammeters are designed for measurement of low current. For measuring high current, the shunt is connected in parallel to the ammeter. The significant portion of the current passes to the shunt because of the low resistance path and little amount of current passes through the ammeter. The shunt is connected in parallel to the ammeter because of which the voltage drops across the meter and shunt remain the same. Thus, the movement of the pointer is not affected by the shunt. Let us consider that the current to be measured is I. The circuit has ammeter and shunt connected parallel to each other. The ammeter is designed for measurement of small current say, Im. The magnitude of the current I passes through the meter is very high, and it will burn the meter. So, for measuring the current I the shunt is required in the circuit. As the shunt connects in parallel with the ammeter, thus the same voltage drops occur between them:IShRSH = ImRm∴ RSH = ImRm/ISHShunt current ISH = I – ImSo, RSH = ImRm/(I – Im)∴ I/Im = 1 + (Rm/RSH)The ratio of the total current to the current required for the movement of the ammeter coil is called the multiplying power of the shunt.∴ The multiplying power = m = I/ImRSH = Rm / (m – 1)The following are the requirements of the shunt.• The resistance of the shunt should remain constant with time.• The temperature of the material should remain the same even though substantial current flows through the circuit.Current through shunt is

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A wire whose resistance 0.1/cm is bent in the form of a square ABCD of side 10 cm. An exactly similar wire is connect across the points B and D. What will be the equivalent resistance between the other two corners A and C of the square?If a 2V battery be connected between A and C,then what will be the current drawn from the battery? If an ammeter be connected B and D,what will it read?
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A wire whose resistance 0.1/cm is bent in the form of a square ABCD of side 10 cm. An exactly similar wire is connect across the points B and D. What will be the equivalent resistance between the other two corners A and C of the square?If a 2V battery be connected between A and C,then what will be the current drawn from the battery? If an ammeter be connected B and D,what will it read? for Class 12 2024 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about A wire whose resistance 0.1/cm is bent in the form of a square ABCD of side 10 cm. An exactly similar wire is connect across the points B and D. What will be the equivalent resistance between the other two corners A and C of the square?If a 2V battery be connected between A and C,then what will be the current drawn from the battery? If an ammeter be connected B and D,what will it read? covers all topics & solutions for Class 12 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A wire whose resistance 0.1/cm is bent in the form of a square ABCD of side 10 cm. An exactly similar wire is connect across the points B and D. What will be the equivalent resistance between the other two corners A and C of the square?If a 2V battery be connected between A and C,then what will be the current drawn from the battery? If an ammeter be connected B and D,what will it read?.
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