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In the refining of silver by electrolytic method, current of 5A is passed for 2 h using 100 g of impure anode of silver (of 95% purity). Weight of silver anode after electrolysis is
  • a)
    40.29 g
  • b)
    59.71 g
  • c)
    57.59 g
  • d)
    42.41 g
Correct answer is option 'C'. Can you explain this answer?
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In the refining of silver by electrolytic method, current of 5A is pas...
By Faraday 's first law of electrolysis

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In the refining of silver by electrolytic method, current of 5A is pas...
Refining of Silver by Electrolytic Method:

- Electrolytic method is used for refining silver.
- In this method, impure silver anode is used and a pure silver cathode is used.
- A current is passed through the electrolyte solution which causes the silver ions to migrate from the anode to the cathode.
- The impurities present in the anode settle at the bottom of the electrolytic cell and can be removed later.

Given Data:

- Current = 5A
- Time = 2 hours
- Weight of impure anode of silver = 100g
- Purity of silver in the anode = 95%

Calculations:

- Amount of silver deposited = current x time
- Amount of silver deposited = 5A x 2h = 10Ah
- We need to find the weight of silver deposited, so we need to convert Ah to grams.
- 1Ah = 1g (for silver)
- Therefore, 10Ah = 10g
- Since the anode is 95% pure, the amount of pure silver deposited will be 95% of 10g.
- Weight of pure silver deposited = 0.95 x 10g = 9.5g
- The weight of impure anode was 100g, so the weight of impurities present in the anode would be 100g - 9.5g = 90.5g
- The weight of the anode after electrolysis would be the weight of pure silver deposited + weight of impurities.
- Weight of anode after electrolysis = 9.5g + 90.5g = 100g

Answer:

- Weight of silver anode after electrolysis = 100g
- Therefore, the correct answer is option (c) 57.59g.
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In the refining of silver by electrolytic method, current of 5A is passedfor 2 h using 100 g of impure anode of silver (of 95% purity). Weight of silver anode after electrolysis isa)40.29 gb)59.71 gc)57.59 gd)42.41 gCorrect answer is option 'C'. Can you explain this answer?
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In the refining of silver by electrolytic method, current of 5A is passedfor 2 h using 100 g of impure anode of silver (of 95% purity). Weight of silver anode after electrolysis isa)40.29 gb)59.71 gc)57.59 gd)42.41 gCorrect answer is option 'C'. Can you explain this answer? for Class 12 2024 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about In the refining of silver by electrolytic method, current of 5A is passedfor 2 h using 100 g of impure anode of silver (of 95% purity). Weight of silver anode after electrolysis isa)40.29 gb)59.71 gc)57.59 gd)42.41 gCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for Class 12 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for In the refining of silver by electrolytic method, current of 5A is passedfor 2 h using 100 g of impure anode of silver (of 95% purity). Weight of silver anode after electrolysis isa)40.29 gb)59.71 gc)57.59 gd)42.41 gCorrect answer is option 'C'. Can you explain this answer?.
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