Consider the function f ( x ) = | x - 1 |+ x2 , w here x∈R .Which...
f(x) = | x - l | + x
2 x ∈
Rf
1 (x ) = |x - l |, f
2(x) = x
2f
1 (x) and f
2{x) both are continuous.
Hence f(x) is continuous.
f(x) in differentiable at x = 0
f
1(x) is not differentiable at x = 1.
Hence(fx) is continuous but not differentiable at x= 1
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Consider the function f ( x ) = | x - 1 |+ x2 , w here x∈R .Which...
Explanation:
Definition of Continuity and Differentiability:
- A function f(x) is said to be continuous at a point x = c if the limit of f(x) as x approaches c exists and is equal to f(c).
- A function f(x) is said to be differentiable at a point x = c if the derivative of f(x) exists at x = c.
Given Function:
f(x) = |x - 1| + x^2
Analysis:
- At x = 1, the function f(x) can be rewritten as f(x) = |1 - 1| + 1^2 = 1, which is a continuous function at x = 1.
- At x = 0, the function f(x) can be rewritten as f(x) = |0 - 1| + 0^2 = 1, which is also a continuous function at x = 0.
- However, when checking the differentiability at these points, we need to consider the behavior of the function as it approaches these points.
Explanation of Correct Answer:
- The function f(x) is continuous but not differentiable at x = 1, as the function |x - 1| has a sharp point at x = 1 where the function is not smooth.
- At x = 0, the function f(x) is also continuous but not differentiable, as the function |x - 1| has a sharp point at x = 0 as well.
Therefore, option B, "f(x) is continuous but not differentiable at x = 1," is the correct statement based on the given function f(x) = |x - 1| + x^2.