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Consider the two lines x + y + 1 = 0 and 3x + 2y + 1 = 0
Q. What is the equation of the line passing through the point of intersection of the given lines and parallel to y-axis?
- a)x + 1 = 0
- b)x - 1 = 0
- c)x - 2 = 0
- d)x + 2 = 0
Correct answer is option 'B'. Can you explain this answer?
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Verified Answer
Consider the two lines x + y + 1 = 0 and 3x + 2y + 1 = 0Q. What is the...
Equations of lines
x+ y + 1 = 0
3x+2y+ 1=0
Points of intersection (1, -2).
Equation of y-axis
x = 0
Equation of line parallel to x -axis is
x = k
If this line passes through (1,-2 then)
x = 1
Hence equation of line which passes through point of intersection of given line (1, -2) and parallel to y-axis
x = 1
⇒ x-1= 0
x+ y + 1 = 0
3x+2y+ 1=0
Points of intersection (1, -2).
Equation of y-axis
x = 0
Equation of line parallel to x -axis is
x = k
If this line passes through (1,-2 then)
x = 1
Hence equation of line which passes through point of intersection of given line (1, -2) and parallel to y-axis
x = 1
⇒ x-1= 0
Most Upvoted Answer
Consider the two lines x + y + 1 = 0 and 3x + 2y + 1 = 0Q. What is the...
Given Lines:
The given lines are:
1. x + y + 1 = 0
2. 3x + 2y + 1 = 0
Finding Intersection Point:
To find the point of intersection of the given lines, we need to solve the two equations simultaneously.
Solving the equations:
x + y + 1 = 0
3x + 2y + 1 = 0
We get the point of intersection as (-1, 0).
Equation of Line Parallel to y-axis:
A line parallel to the y-axis has a slope that tends to infinity. Therefore, the equation of the line passing through the point of intersection and parallel to the y-axis will be in the form of x = k, where k is a constant.
Answer:
The equation of the line passing through the point of intersection of the given lines and parallel to the y-axis is x - 1 = 0, which simplifies to x = 1. Hence, the correct answer is option B.
The given lines are:
1. x + y + 1 = 0
2. 3x + 2y + 1 = 0
Finding Intersection Point:
To find the point of intersection of the given lines, we need to solve the two equations simultaneously.
Solving the equations:
x + y + 1 = 0
3x + 2y + 1 = 0
We get the point of intersection as (-1, 0).
Equation of Line Parallel to y-axis:
A line parallel to the y-axis has a slope that tends to infinity. Therefore, the equation of the line passing through the point of intersection and parallel to the y-axis will be in the form of x = k, where k is a constant.
Answer:
The equation of the line passing through the point of intersection of the given lines and parallel to the y-axis is x - 1 = 0, which simplifies to x = 1. Hence, the correct answer is option B.
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Consider the two lines x + y + 1 = 0 and 3x + 2y + 1 = 0Q. What is the equation of the line passing through the point of intersection of the given lines and parallel to y-axis?a)x + 1 = 0b)x - 1 = 0c)x - 2 = 0d)x + 2 = 0Correct answer is option 'B'. Can you explain this answer?
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