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The value of the thermal voltage at room temperature can be approximated as
- a)25 mV
- b)30 mV
- c)35 mV
- d)40 mV
Correct answer is option 'A'. Can you explain this answer?
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The value of the thermal voltage at room temperature can be approximat...
Thermal voltage is given by kT/q which at T = 25 degrees Celsius is approximately 25 mV.
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Introduction:
The thermal voltage is a fundamental concept in semiconductor physics and is related to the temperature of a material. It is often used to describe the behavior of diodes and transistors. In this question, we are asked to approximate the value of the thermal voltage at room temperature.
Explanation:
The thermal voltage is given by the equation:
Vt = (k * T) / q
Where:
Vt is the thermal voltage
k is the Boltzmann constant (1.38 x 10^-23 J/K)
T is the temperature in Kelvin
q is the charge of an electron (1.6 x 10^-19 C)
Converting room temperature to Kelvin:
Room temperature is typically defined as 25 degrees Celsius. To convert this temperature to Kelvin, we add 273.15 to it:
T = 25 + 273.15 = 298.15 K
Calculating the thermal voltage:
Now we can plug the values into the equation to calculate the thermal voltage:
Vt = (1.38 x 10^-23 J/K * 298.15 K) / (1.6 x 10^-19 C)
Simplifying the equation:
Vt = 8.617 x 10^-5 J/C
Converting the thermal voltage to millivolts:
To convert the thermal voltage to millivolts, we divide it by 1 x 10^-3:
Vt = (8.617 x 10^-5 J/C) / (1 x 10^-3) = 8.617 x 10^-2 V = 86.17 mV
Conclusion:
Therefore, the value of the thermal voltage at room temperature is approximately 86.17 mV. However, none of the given options match this value. Therefore, it seems there might be an error in the options provided.
The thermal voltage is a fundamental concept in semiconductor physics and is related to the temperature of a material. It is often used to describe the behavior of diodes and transistors. In this question, we are asked to approximate the value of the thermal voltage at room temperature.
Explanation:
The thermal voltage is given by the equation:
Vt = (k * T) / q
Where:
Vt is the thermal voltage
k is the Boltzmann constant (1.38 x 10^-23 J/K)
T is the temperature in Kelvin
q is the charge of an electron (1.6 x 10^-19 C)
Converting room temperature to Kelvin:
Room temperature is typically defined as 25 degrees Celsius. To convert this temperature to Kelvin, we add 273.15 to it:
T = 25 + 273.15 = 298.15 K
Calculating the thermal voltage:
Now we can plug the values into the equation to calculate the thermal voltage:
Vt = (1.38 x 10^-23 J/K * 298.15 K) / (1.6 x 10^-19 C)
Simplifying the equation:
Vt = 8.617 x 10^-5 J/C
Converting the thermal voltage to millivolts:
To convert the thermal voltage to millivolts, we divide it by 1 x 10^-3:
Vt = (8.617 x 10^-5 J/C) / (1 x 10^-3) = 8.617 x 10^-2 V = 86.17 mV
Conclusion:
Therefore, the value of the thermal voltage at room temperature is approximately 86.17 mV. However, none of the given options match this value. Therefore, it seems there might be an error in the options provided.
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The value of the thermal voltage at room temperature can be approximated asa)25 mVb)30 mVc)35 mVd)40 mVCorrect answer is option 'A'. Can you explain this answer?
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