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For a reaction ,2N2O5 gives 4NO2+O2 rate and rate constatnt are 1.02*10^-4mol L-1s-1 and 3.48*10^-5s-1respectively the concentrartion o f N2O5 in M
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For a reaction ,2N2O5 gives 4NO2+O2 rate and rate constatnt are 1.02*1...
Answer:
Given:
Reaction: 2N2O5 → 4NO2 + O2
Rate constant, k = 3.48 × 10^-5 s^-1
Rate, r = 1.02 × 10^-4 mol L^-1 s^-1
Calculating the Concentration of N2O5:
The rate law for this reaction can be written as:
r = k[N2O5]^2
Where,
k = rate constant
[N2O5] = concentration of N2O5
We can rearrange the formula to solve for [N2O5]:
[N2O5]^2 = r/k
[N2O5]^2 = (1.02 × 10^-4 mol L^-1 s^-1) / (3.48 × 10^-5 s^-1)
[N2O5]^2 = 2.93103448276 mol L^-1
[N2O5] = √(2.93103448276 mol L^-1)
[N2O5] = 1.71 mol L^-1
Therefore, the concentration of N2O5 is 1.71 M.
Explanation:
The given reaction is a second-order reaction, which means the rate of the reaction is proportional to the square of the concentration of N2O5. The rate constant for the reaction is also given. Using the rate equation and the rate constant, we can calculate the concentration of N2O5.
The formula for calculating the concentration of N2O5 involves squaring the concentration. Therefore, we first calculate the square of the rate and divide it by the rate constant. After calculating the square root of the result, we get the concentration of N2O5.
In conclusion, the concentration of N2O5 is 1.71 M.
Given:
Reaction: 2N2O5 → 4NO2 + O2
Rate constant, k = 3.48 × 10^-5 s^-1
Rate, r = 1.02 × 10^-4 mol L^-1 s^-1
Calculating the Concentration of N2O5:
The rate law for this reaction can be written as:
r = k[N2O5]^2
Where,
k = rate constant
[N2O5] = concentration of N2O5
We can rearrange the formula to solve for [N2O5]:
[N2O5]^2 = r/k
[N2O5]^2 = (1.02 × 10^-4 mol L^-1 s^-1) / (3.48 × 10^-5 s^-1)
[N2O5]^2 = 2.93103448276 mol L^-1
[N2O5] = √(2.93103448276 mol L^-1)
[N2O5] = 1.71 mol L^-1
Therefore, the concentration of N2O5 is 1.71 M.
Explanation:
The given reaction is a second-order reaction, which means the rate of the reaction is proportional to the square of the concentration of N2O5. The rate constant for the reaction is also given. Using the rate equation and the rate constant, we can calculate the concentration of N2O5.
The formula for calculating the concentration of N2O5 involves squaring the concentration. Therefore, we first calculate the square of the rate and divide it by the rate constant. After calculating the square root of the result, we get the concentration of N2O5.
In conclusion, the concentration of N2O5 is 1.71 M.
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For a reaction ,2N2O5 gives 4NO2+O2 rate and rate constatnt are 1.02*10^-4mol L-1s-1 and 3.48*10^-5s-1respectively the concentrartion o f N2O5 in M?
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For a reaction ,2N2O5 gives 4NO2+O2 rate and rate constatnt are 1.02*10^-4mol L-1s-1 and 3.48*10^-5s-1respectively the concentrartion o f N2O5 in M? for Class 12 2025 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about For a reaction ,2N2O5 gives 4NO2+O2 rate and rate constatnt are 1.02*10^-4mol L-1s-1 and 3.48*10^-5s-1respectively the concentrartion o f N2O5 in M? covers all topics & solutions for Class 12 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for For a reaction ,2N2O5 gives 4NO2+O2 rate and rate constatnt are 1.02*10^-4mol L-1s-1 and 3.48*10^-5s-1respectively the concentrartion o f N2O5 in M?.
For a reaction ,2N2O5 gives 4NO2+O2 rate and rate constatnt are 1.02*10^-4mol L-1s-1 and 3.48*10^-5s-1respectively the concentrartion o f N2O5 in M? for Class 12 2025 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about For a reaction ,2N2O5 gives 4NO2+O2 rate and rate constatnt are 1.02*10^-4mol L-1s-1 and 3.48*10^-5s-1respectively the concentrartion o f N2O5 in M? covers all topics & solutions for Class 12 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for For a reaction ,2N2O5 gives 4NO2+O2 rate and rate constatnt are 1.02*10^-4mol L-1s-1 and 3.48*10^-5s-1respectively the concentrartion o f N2O5 in M?.
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