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A ballof mass 3kg collides with a wall with velocity 10m/s at an angle of 30 with wall and after collision reflects at the same angle with the same speed. The change in momentum of ball in MKS unit is ?
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Calculation of Change in Momentum of a Ball


Given:


  • Mass of the ball, m = 3 kg

  • Velocity of the ball before collision, u = 10 m/s

  • Angle of incidence, θ = 30°

  • Velocity of the ball after collision, v = 10 m/s



Formula:


  • Momentum, p = m * v

  • Change in momentum, Δp = pf - pi



Calculation:

Before collision, the momentum of the ball can be calculated as:

pi = m * u = 3 * 10 = 30 kg m/s


After collision, the momentum of the ball can be calculated as:

pf = m * v = 3 * 10 = 30 kg m/s


Therefore, the change in momentum of the ball can be calculated as:

Δp = pf - pi = 30 - 30 = 0 kg m/s


Explanation:

The change in momentum of the ball is zero since the velocity of the ball before and after collision is the same. This can be explained by the law of conservation of momentum which states that the total momentum of a system remains constant if no external forces act on it. In this case, the ball and the wall form a closed system and the only force acting on the ball is the normal force exerted by the wall. Since this force is perpendicular to the velocity of the ball, it does not affect the momentum of the ball. Hence, the momentum of the ball before and after collision remains the same, resulting in zero change in momentum.
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A ballof mass 3kg collides with a wall with velocity 10m/s at an angle of 30 with wall and after collision reflects at the same angle with the same speed. The change in momentum of ball in MKS unit is ?
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