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Passage II
The standard half-cell reduction potential of  
Fe3+(aq) | Fe is -0.036V and that of OH- | Fe(OH3)(s) | Feis -0.786V.
Q.
The value of loge Ksp for Fe(OH)3 at 298 K is
  • a)
    -38.1
  • b)
    +87.7
  • c)
    -96.0
  • d)
    -87.7
Correct answer is option 'D'. Can you explain this answer?
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Verified Answer
Passage IIThe standard half-cell reduction potentialof Fe3+(aq) | Fe i...

Above reaction is the net reaction in a cell for determination of Ksp.
Thus,
Anode
Fe → Fe3+ (aq) + 3e-, E0ox = 0.036V
Half - cell is Fe|Fe3+ (aq). OH-(aq)
Cathode
Fe(OH)3(s) + 3e- → Fe+ 3OH-, E0red = -0.786 V
Half-cell set up is Fe(OH)3(s)|Fe
complete cell is Fe|Fe3+(aq), OH- (aq)||Fe(OH)3 (s)|Fe
and E0cell = E0ox + E0red = 0.036 + (-0.786) = -0.750V
By net reaction, K = Ksp = [Fe3+][OH-]3
∴ 
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Passage IIThe standard half-cell reduction potentialof Fe3+(aq) | Fe i...
Calculation of Ksp for Fe(OH)3

Half-cell reactions:
Fe3+ (aq) + 3e- → Fe(s) E° = -0.036 V
Fe(OH)3 (s) + 3e- → Fe(s) + 3OH- (aq) E° = -0.786 V

Overall reaction: Fe3+ (aq) + 3OH- (aq) → Fe(OH)3 (s)

Standard emf of the cell, E°cell = E°cathode – E°anode
E°cell = 0.786 – (-0.036) = 0.822 V

The equilibrium constant expression for the above overall reaction is:
Ksp = [Fe3+] [OH-]^3 / [Fe(OH)3]

The standard free energy change for the above reaction is:
ΔG° = -nFE°cell = -3 x 96500 x 0.822 = -237310 J/mol

The relationship between ΔG° and Ksp is given by the equation:
ΔG° = -RT ln Ksp
-237310 = -8.314 x 298 x ln Ksp
ln Ksp = -87.7

Therefore, Ksp = e^-87.7 = 2.42 x 10^-38

Hence, the value of logeKsp for Fe(OH)3 at 298 K is -87.7.
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Read the passage given below and answer the following questions:Reductive alkylation is the term applied to the process of introducing alkyl groups into ammonia or a primary or secondary amine by means of an aldehyde or ketone in the presence of a reducing agent. The present discussion is limited to those reductive alkylations in which the reducing agent is hydrogen and a catalyst or "nascent" hydrogen, usually from a metalacid combination; most of these reductive alkylations have been carried out with hydrogen and a catalyst. The principal variation excluded is that in which the reducing agent is formic acid or one of its derivatives; this modification is known as the Leuckart reaction. The process of reductive alkylation of ammonia consists in the addition of ammonia to a carbonyl compound and reduction of the addition compound or its dehydration product. The reaction usually is carried out in ethanol solution when the reduction is to be effected catalytically:Since the primary amine is formed in the presence of the aldehyde it may react in the same way as ammonia, yielding an additional compound, a Schiff's base (RCH= NCH2R) and finally, a secondary amine. Similarly, the primary amine may react with the imine, forming an addition product which also is reduced to a secondary amine Finally, the secondary amine may react with either the aldehyde or the imine to give products which are reduced to tertiary amines.Similar reactions may occur when the carbonyl compound employed is a ketone.Q. The reaction of ammonia and its derivatives with aldehydes is called

Passage IIThe standard half-cell reduction potentialof Fe3+(aq) | Fe is -0.036Vand that ofOH- | Fe(OH3)(s) | Feis -0.786V.Q. The value of logeKsp for Fe(OH)3 at 298 K isa)-38.1b)+87.7c)-96.0d)-87.7Correct answer is option 'D'. Can you explain this answer?
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Passage IIThe standard half-cell reduction potentialof Fe3+(aq) | Fe is -0.036Vand that ofOH- | Fe(OH3)(s) | Feis -0.786V.Q. The value of logeKsp for Fe(OH)3 at 298 K isa)-38.1b)+87.7c)-96.0d)-87.7Correct answer is option 'D'. Can you explain this answer? for Class 12 2024 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about Passage IIThe standard half-cell reduction potentialof Fe3+(aq) | Fe is -0.036Vand that ofOH- | Fe(OH3)(s) | Feis -0.786V.Q. The value of logeKsp for Fe(OH)3 at 298 K isa)-38.1b)+87.7c)-96.0d)-87.7Correct answer is option 'D'. Can you explain this answer? covers all topics & solutions for Class 12 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Passage IIThe standard half-cell reduction potentialof Fe3+(aq) | Fe is -0.036Vand that ofOH- | Fe(OH3)(s) | Feis -0.786V.Q. The value of logeKsp for Fe(OH)3 at 298 K isa)-38.1b)+87.7c)-96.0d)-87.7Correct answer is option 'D'. Can you explain this answer?.
Solutions for Passage IIThe standard half-cell reduction potentialof Fe3+(aq) | Fe is -0.036Vand that ofOH- | Fe(OH3)(s) | Feis -0.786V.Q. The value of logeKsp for Fe(OH)3 at 298 K isa)-38.1b)+87.7c)-96.0d)-87.7Correct answer is option 'D'. Can you explain this answer? in English & in Hindi are available as part of our courses for Class 12. Download more important topics, notes, lectures and mock test series for Class 12 Exam by signing up for free.
Here you can find the meaning of Passage IIThe standard half-cell reduction potentialof Fe3+(aq) | Fe is -0.036Vand that ofOH- | Fe(OH3)(s) | Feis -0.786V.Q. The value of logeKsp for Fe(OH)3 at 298 K isa)-38.1b)+87.7c)-96.0d)-87.7Correct answer is option 'D'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of Passage IIThe standard half-cell reduction potentialof Fe3+(aq) | Fe is -0.036Vand that ofOH- | Fe(OH3)(s) | Feis -0.786V.Q. The value of logeKsp for Fe(OH)3 at 298 K isa)-38.1b)+87.7c)-96.0d)-87.7Correct answer is option 'D'. Can you explain this answer?, a detailed solution for Passage IIThe standard half-cell reduction potentialof Fe3+(aq) | Fe is -0.036Vand that ofOH- | Fe(OH3)(s) | Feis -0.786V.Q. The value of logeKsp for Fe(OH)3 at 298 K isa)-38.1b)+87.7c)-96.0d)-87.7Correct answer is option 'D'. Can you explain this answer? has been provided alongside types of Passage IIThe standard half-cell reduction potentialof Fe3+(aq) | Fe is -0.036Vand that ofOH- | Fe(OH3)(s) | Feis -0.786V.Q. The value of logeKsp for Fe(OH)3 at 298 K isa)-38.1b)+87.7c)-96.0d)-87.7Correct answer is option 'D'. Can you explain this answer? theory, EduRev gives you an ample number of questions to practice Passage IIThe standard half-cell reduction potentialof Fe3+(aq) | Fe is -0.036Vand that ofOH- | Fe(OH3)(s) | Feis -0.786V.Q. The value of logeKsp for Fe(OH)3 at 298 K isa)-38.1b)+87.7c)-96.0d)-87.7Correct answer is option 'D'. Can you explain this answer? tests, examples and also practice Class 12 tests.
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