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White heavy precipitates are formed when BaCl2 is added to a clear solution of compound A. Precipitates are insoluble in dilute HCl. Then, the compound A is -
- a)a bicarbonate
- b)a carbonate
- c)a sulphate
- d)a chloride
Correct answer is option 'C'. Can you explain this answer?
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White heavy precipitates are formed when BaCl2is added to a clear solu...
BaSO4 is insoluble in HCl
but BaCO3 & BaCl2 dissoluble in HCl
but BaCO3 & BaCl2 dissoluble in HCl
Most Upvoted Answer
White heavy precipitates are formed when BaCl2is added to a clear solu...
Solution:
Precipitation Reaction:
When BaCl2 is added to compound A, white heavy precipitates are formed. This indicates that a chemical reaction has occurred between BaCl2 and compound A, resulting in the formation of an insoluble compound.
Solubility in Dilute HCl:
The precipitates formed are insoluble in dilute HCl. This means that when the precipitates are added to dilute HCl, they do not dissolve and remain as a solid. This characteristic can be used to identify the compound A.
Possible Compounds:
To determine the compound A, we need to consider the possible compounds that can form insoluble precipitates when reacted with BaCl2 and are also insoluble in dilute HCl.
The options given are:
a) a bicarbonate
b) a carbonate
c) a sulphate
d) a chloride
Reasoning:
- Bicarbonates (option a) are generally soluble in water and do not form precipitates with BaCl2. Therefore, compound A is not a bicarbonate.
- Carbonates (option b) can react with BaCl2 to form white precipitates. However, carbonates are soluble in dilute HCl. Therefore, compound A is not a carbonate.
- Sulphates (option c) can react with BaCl2 to form white precipitates and are insoluble in dilute HCl. Therefore, compound A can be a sulphate.
- Chlorides (option d) do not form precipitates with BaCl2. Therefore, compound A is not a chloride.
Conclusion:
Based on the given information, the compound A is likely to be a sulphate (option c) since it forms white precipitates with BaCl2 and these precipitates are insoluble in dilute HCl.
Precipitation Reaction:
When BaCl2 is added to compound A, white heavy precipitates are formed. This indicates that a chemical reaction has occurred between BaCl2 and compound A, resulting in the formation of an insoluble compound.
Solubility in Dilute HCl:
The precipitates formed are insoluble in dilute HCl. This means that when the precipitates are added to dilute HCl, they do not dissolve and remain as a solid. This characteristic can be used to identify the compound A.
Possible Compounds:
To determine the compound A, we need to consider the possible compounds that can form insoluble precipitates when reacted with BaCl2 and are also insoluble in dilute HCl.
The options given are:
a) a bicarbonate
b) a carbonate
c) a sulphate
d) a chloride
Reasoning:
- Bicarbonates (option a) are generally soluble in water and do not form precipitates with BaCl2. Therefore, compound A is not a bicarbonate.
- Carbonates (option b) can react with BaCl2 to form white precipitates. However, carbonates are soluble in dilute HCl. Therefore, compound A is not a carbonate.
- Sulphates (option c) can react with BaCl2 to form white precipitates and are insoluble in dilute HCl. Therefore, compound A can be a sulphate.
- Chlorides (option d) do not form precipitates with BaCl2. Therefore, compound A is not a chloride.
Conclusion:
Based on the given information, the compound A is likely to be a sulphate (option c) since it forms white precipitates with BaCl2 and these precipitates are insoluble in dilute HCl.
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White heavy precipitates are formed when BaCl2is added to a clear solution of compound A. Precipitates are insoluble in dilute HCl. Then, the compound A is -a)a bicarbonateb)a carbonatec)a sulphated)a chlorideCorrect answer is option 'C'. Can you explain this answer?
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White heavy precipitates are formed when BaCl2is added to a clear solution of compound A. Precipitates are insoluble in dilute HCl. Then, the compound A is -a)a bicarbonateb)a carbonatec)a sulphated)a chlorideCorrect answer is option 'C'. Can you explain this answer? for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about White heavy precipitates are formed when BaCl2is added to a clear solution of compound A. Precipitates are insoluble in dilute HCl. Then, the compound A is -a)a bicarbonateb)a carbonatec)a sulphated)a chlorideCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for White heavy precipitates are formed when BaCl2is added to a clear solution of compound A. Precipitates are insoluble in dilute HCl. Then, the compound A is -a)a bicarbonateb)a carbonatec)a sulphated)a chlorideCorrect answer is option 'C'. Can you explain this answer?.
Solutions for White heavy precipitates are formed when BaCl2is added to a clear solution of compound A. Precipitates are insoluble in dilute HCl. Then, the compound A is -a)a bicarbonateb)a carbonatec)a sulphated)a chlorideCorrect answer is option 'C'. Can you explain this answer? in English & in Hindi are available as part of our courses for Class 11.
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White heavy precipitates are formed when BaCl2is added to a clear solution of compound A. Precipitates are insoluble in dilute HCl. Then, the compound A is -a)a bicarbonateb)a carbonatec)a sulphated)a chlorideCorrect answer is option 'C'. Can you explain this answer?, a detailed solution for White heavy precipitates are formed when BaCl2is added to a clear solution of compound A. Precipitates are insoluble in dilute HCl. Then, the compound A is -a)a bicarbonateb)a carbonatec)a sulphated)a chlorideCorrect answer is option 'C'. Can you explain this answer? has been provided alongside types of White heavy precipitates are formed when BaCl2is added to a clear solution of compound A. Precipitates are insoluble in dilute HCl. Then, the compound A is -a)a bicarbonateb)a carbonatec)a sulphated)a chlorideCorrect answer is option 'C'. Can you explain this answer? theory, EduRev gives you an
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