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A thin cylinder of inner radius 500 mm and thickness 10 mm is subjected to an internal pressure of 5 MPa. The average circumferential (hoop) stress in MPa isb
  • a)
    100
  • b)
    250
  • c)
    500
  • d)
    1000 
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
A thin cylinder of inner radius 500 mm and thickness 10 mm is subjecte...
Inner radius (r) = 500 mm
Thickness (t) = 10 mm
Internal pressure (p) = 5 MPa
Hoop stress 
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Most Upvoted Answer
A thin cylinder of inner radius 500 mm and thickness 10 mm is subjecte...
Given:
Inner radius of cylinder (r₁) = 500 mm = 0.5 m
Thickness of cylinder (t) = 10 mm = 0.01 m
Internal pressure (P) = 5 MPa

To find:
Average circumferential stress (σ_circ)

Solution:
The average circumferential stress in a thin-walled cylinder can be calculated using the formula:

σ_circ = (P * r₁) / t

where,
σ_circ = average circumferential stress
P = internal pressure
r₁ = inner radius of cylinder
t = thickness of cylinder

Substituting the given values:
σ_circ = (5 * 0.5) / 0.01
σ_circ = 2.5 / 0.01
σ_circ = 250 MPa

Answer:
The average circumferential stress in the thin cylinder is 250 MPa. Therefore, the correct answer is option B.
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A thin cylinder of inner radius 500 mm and thickness 10 mm is subjected to an internal pressure of 5 MPa. The average circumferential (hoop) stress in MPa isba)100b)250c)500d)1000Correct answer is option 'B'. Can you explain this answer?
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