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In a certain electronic transitions in the hydrogen atoms from an initial state to final state the difference in the orbit radius r1-r2 is 24 times the first Bohr radius
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In a certain electronic transitions in the hydrogen atoms from an init...
Explanation of Electronic Transitions in Hydrogen Atoms


The electronic transitions in hydrogen atoms occur when an electron transitions from one energy level to another. The difference in energy between the initial and final energy states determines the frequency of the electromagnetic radiation emitted or absorbed. The energy levels in hydrogen atoms are quantized, meaning that only certain energies are allowed.


Difference in Orbit Radius


The difference in the orbit radius between the initial and final states is given by the equation:


r1 - r2 = a0 * (n2^2 - n1^2)


Where:


  • r1 and r2 are the initial and final orbit radii, respectively

  • a0 is the first Bohr radius (0.529 Å)

  • n1 and n2 are the principal quantum numbers of the initial and final states, respectively



Given that r1 - r2 = 24a0, we can solve for n1 and n2:


24a0 = a0 * (n2^2 - n1^2)


24 = n2^2 - n1^2


Since n2 > n1, the only possible integer values for n1 and n2 that satisfy this equation are:



  • n1 = 1

  • n2 = 5



Therefore, the electronic transition is from the n=5 to the n=1 energy level in the hydrogen atom.
Community Answer
In a certain electronic transitions in the hydrogen atoms from an init...
Question Completion :Find Initial and Final States.(i, f)
Final Answer : Initial State = 3
Final State = 4

Steps and Understanding :
1)We know that radius of an orbit for a particular atom is proportional to n^2 where n is the orbit number.
Then,
R = k n^2
where k is constant for a particular atom.

2) According to the question,

R(f) - R(i) =7* R(1)
=> k (f)^2 - k(i)^2 = 7*k*(1)^2

Since,7 is prime number and f> i,
so,


On solving above equations,


3) So, Required initial state n = 3
Final State n = 4

Read more on Brainly.in - https://brainly.in/question/4130041#readmore
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A dense collection of equal number of electrons and positive ions is called neutral plasma. Certain solids containing fixed positive ions surrounded by free electrons can be treated as neutral plasma. Let N be the number density of free electrons, each of mass m. When the electrons are subjected to an electric field, they are displaced relatively away from the heavy positive ions. If the electric field becomes zero, the electrons begin to oscillate about the positive ions with a natural angular frequency wP which is called the plasma frequency. To sustain the oscillations, a time varying electric field needs to be applied that has an angular frequency w, where a part of the energy is absorbed and a part of it is reflected. As w approaches wP, all the free electrons are set to resonance together and all the energy is reflected. This is the explanation of high reflectivity of metals.Taking the electronic charge as e and the permittivity as ε0, use dimensional analysis to determine the correct expression for wP.

Can you explain the answer of this question below:A dense collection of equal number of electrons and positive ions is called neutral plasma. Certain solids containing fixed positive ions surrounded by free electrons can be treated as neutral plasma. Let N be the number density of free electrons, each of mass m. When the electrons are subjected to an electric field, they are displaced relatively away from the heavy positive ions. If the electric field becomes zero, the electrons begin to oscillate about the positive ions with a natural angular frequency wP which is called the plasma frequency. To sustain the oscillations, a time varying electric field needs to be applied that has an angular frequency w, where a part of the energy is absorbed and a part of it is reflected. As w approaches wP, all the free electrons are set to resonance together and all the energy is reflected. This is the explanation of high reflectivity of metals.Taking the electronic charge as e and the permittivity as 0, use dimensional analysis to determine the correct expression for wP. [JEE-2011]A:B:C:D:The answer is C.

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In a certain electronic transitions in the hydrogen atoms from an initial state to final state the difference in the orbit radius r1-r2 is 24 times the first Bohr radius
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