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In a certain electronic transitions in the hydrogen atoms from an initial state to final state the difference in the orbit radius r1-r2 is 24 times the first Bohr radius
Most Upvoted Answer
In a certain electronic transitions in the hydrogen atoms from an init...
Explanation of Electronic Transitions in Hydrogen Atoms
The electronic transitions in hydrogen atoms occur when an electron transitions from one energy level to another. The difference in energy between the initial and final energy states determines the frequency of the electromagnetic radiation emitted or absorbed. The energy levels in hydrogen atoms are quantized, meaning that only certain energies are allowed.
Difference in Orbit Radius
The difference in the orbit radius between the initial and final states is given by the equation:
r1 - r2 = a0 * (n2^2 - n1^2)
Where:
- r1 and r2 are the initial and final orbit radii, respectively
- a0 is the first Bohr radius (0.529 Å)
- n1 and n2 are the principal quantum numbers of the initial and final states, respectively
Given that r1 - r2 = 24a0, we can solve for n1 and n2:
24a0 = a0 * (n2^2 - n1^2)
24 = n2^2 - n1^2
Since n2 > n1, the only possible integer values for n1 and n2 that satisfy this equation are:
- n1 = 1
- n2 = 5
Therefore, the electronic transition is from the n=5 to the n=1 energy level in the hydrogen atom.
Community Answer
In a certain electronic transitions in the hydrogen atoms from an init...
Question Completion :Find Initial and Final States.(i, f)
Final Answer : Initial State = 3
Final State = 4
Steps and Understanding :
1)We know that radius of an orbit for a particular atom is proportional to n^2 where n is the orbit number.
Then,
R = k n^2
where k is constant for a particular atom.
2) According to the question,
R(f) - R(i) =7* R(1)
=> k (f)^2 - k(i)^2 = 7*k*(1)^2
Since,7 is prime number and f> i,
so,
On solving above equations,
3) So, Required initial state n = 3
Final State n = 4
Read more on Brainly.in - https://brainly.in/question/4130041#readmore
Final Answer : Initial State = 3
Final State = 4
Steps and Understanding :
1)We know that radius of an orbit for a particular atom is proportional to n^2 where n is the orbit number.
Then,
R = k n^2
where k is constant for a particular atom.
2) According to the question,
R(f) - R(i) =7* R(1)
=> k (f)^2 - k(i)^2 = 7*k*(1)^2
Since,7 is prime number and f> i,
so,
On solving above equations,
3) So, Required initial state n = 3
Final State n = 4
Read more on Brainly.in - https://brainly.in/question/4130041#readmore
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In a certain electronic transitions in the hydrogen atoms from an initial state to final state the difference in the orbit radius r1-r2 is 24 times the first Bohr radius
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In a certain electronic transitions in the hydrogen atoms from an initial state to final state the difference in the orbit radius r1-r2 is 24 times the first Bohr radius for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about In a certain electronic transitions in the hydrogen atoms from an initial state to final state the difference in the orbit radius r1-r2 is 24 times the first Bohr radius covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for In a certain electronic transitions in the hydrogen atoms from an initial state to final state the difference in the orbit radius r1-r2 is 24 times the first Bohr radius .
In a certain electronic transitions in the hydrogen atoms from an initial state to final state the difference in the orbit radius r1-r2 is 24 times the first Bohr radius for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about In a certain electronic transitions in the hydrogen atoms from an initial state to final state the difference in the orbit radius r1-r2 is 24 times the first Bohr radius covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for In a certain electronic transitions in the hydrogen atoms from an initial state to final state the difference in the orbit radius r1-r2 is 24 times the first Bohr radius .
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