When two resistance are connected in parallel then the equivalent resistance is 6/5 ohm when one resistance is removed then the effective resistance is 2 ohm the resistance of the wire removed will be?

Question

Answer

If one resistor is of 2ohm then the other would be 1\x

Now,

Since they are connected in parallel,

1/2 + 1/X = 5/6

1\x = 5\6 - 1/2

1\x = 1/3

Therefore X = 3ohm

So,the other resistor was of 3 ohm

Answer

Given Information:
- Equivalent resistance in parallel = 6/5 ohm
- Effective resistance when one resistance is removed = 2 ohm

Solution:

Step 1: Finding the total resistance in parallel
When two resistances are connected in parallel, the formula for calculating the equivalent resistance is:
1/Req = 1/R1 + 1/R2
Given that 1/Req = 6/5, we can rewrite the formula as:
1/(6/5) = 1/R1 + 1/R2
5/6 = 1/R1 + 1/R2
5/6 = (R1 + R2) / (R1 * R2)

Step 2: Finding the resistance of the removed wire
When one resistance is removed, the total resistance becomes 2 ohm. Let's assume the resistance of the wire removed as Rw.
Therefore, the new equation will be:
1/(2) = 1/R1 + 1/Rw
1/(2) = (Rw + R1) / (Rw * R1)

Step 3: Solving the equations
From step 1, we know:
5/6 = (R1 + R2) / (R1 * R2)
From step 2, we know:
1/(2) = (Rw + R1) / (Rw * R1)
By solving these two equations simultaneously, we can find the value of Rw, which will be the resistance of the wire removed.

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