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A body hanging from a spring streches it by 1cm at the earth surface .How much will the same body strech the spring at a place 1600 km above earth surface ? Radius of Earth =6400 km?
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A body hanging from a spring streches it by 1cm at the earth surface ....
Let m be the mass of the body.
Spring constant of the spring is given by:
K = m g / x
K = m g / 1 cm ... 1
here g is accerleration due to gravity near the surface.
Now g at the height 1600km is given as
g(at h) = g/(1 + h / R) ^ 2
After some calculation
g(at h) = g / 1.5625 ... 2
Now extension in spring at this height is given as
x = m g(at h) / K
Substituting the value of g and K from eq 1 and 2 give us a value of x
Value of x would be approx. o.64 cm
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