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In the determination of Young’s modulus using Searle’s method, a wire of length L = 2 m and diameter d = 0.5 mm is used. For a load M = 2.5 kg, an extension l = 0.25 mm in the length of the wire is observed. Quantities d and l are measured using a screw gauge and a micrometer, respectively. They have the same pitch of 0.5 mm. The number of divisions on their circular scale is 100. The contributions to the maximum probable error of the Y measurementa)due to the errors in the measurements of d and l are the same.b)due to the error in the measurement of d is twice that due to the error in the measurement of l .c)due to the error in the measurement of l is twice that due to the error in the measurement of d.d)due to the error in the measurement of d is four times that due to the error in the measurement of l.Correct answer is option 'A'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about In the determination of Young’s modulus using Searle’s method, a wire of length L = 2 m and diameter d = 0.5 mm is used. For a load M = 2.5 kg, an extension l = 0.25 mm in the length of the wire is observed. Quantities d and l are measured using a screw gauge and a micrometer, respectively. They have the same pitch of 0.5 mm. The number of divisions on their circular scale is 100. The contributions to the maximum probable error of the Y measurementa)due to the errors in the measurements of d and l are the same.b)due to the error in the measurement of d is twice that due to the error in the measurement of l .c)due to the error in the measurement of l is twice that due to the error in the measurement of d.d)due to the error in the measurement of d is four times that due to the error in the measurement of l.Correct answer is option 'A'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for In the determination of Young’s modulus using Searle’s method, a wire of length L = 2 m and diameter d = 0.5 mm is used. For a load M = 2.5 kg, an extension l = 0.25 mm in the length of the wire is observed. Quantities d and l are measured using a screw gauge and a micrometer, respectively. They have the same pitch of 0.5 mm. The number of divisions on their circular scale is 100. The contributions to the maximum probable error of the Y measurementa)due to the errors in the measurements of d and l are the same.b)due to the error in the measurement of d is twice that due to the error in the measurement of l .c)due to the error in the measurement of l is twice that due to the error in the measurement of d.d)due to the error in the measurement of d is four times that due to the error in the measurement of l.Correct answer is option 'A'. Can you explain this answer?.

Solutions for In the determination of Young’s modulus using Searle’s method, a wire of length L = 2 m and diameter d = 0.5 mm is used. For a load M = 2.5 kg, an extension l = 0.25 mm in the length of the wire is observed. Quantities d and l are measured using a screw gauge and a micrometer, respectively. They have the same pitch of 0.5 mm. The number of divisions on their circular scale is 100. The contributions to the maximum probable error of the Y measurementa)due to the errors in the measurements of d and l are the same.b)due to the error in the measurement of d is twice that due to the error in the measurement of l .c)due to the error in the measurement of l is twice that due to the error in the measurement of d.d)due to the error in the measurement of d is four times that due to the error in the measurement of l.Correct answer is option 'A'. Can you explain this answer? in English & in Hindi are available as part of our courses for JEE. Download more important topics, notes, lectures and mock test series for JEE Exam by signing up for free.

Here you can find the meaning of In the determination of Young’s modulus using Searle’s method, a wire of length L = 2 m and diameter d = 0.5 mm is used. For a load M = 2.5 kg, an extension l = 0.25 mm in the length of the wire is observed. Quantities d and l are measured using a screw gauge and a micrometer, respectively. They have the same pitch of 0.5 mm. The number of divisions on their circular scale is 100. The contributions to the maximum probable error of the Y measurementa)due to the errors in the measurements of d and l are the same.b)due to the error in the measurement of d is twice that due to the error in the measurement of l .c)due to the error in the measurement of l is twice that due to the error in the measurement of d.d)due to the error in the measurement of d is four times that due to the error in the measurement of l.Correct answer is option 'A'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of In the determination of Young’s modulus using Searle’s method, a wire of length L = 2 m and diameter d = 0.5 mm is used. For a load M = 2.5 kg, an extension l = 0.25 mm in the length of the wire is observed. Quantities d and l are measured using a screw gauge and a micrometer, respectively. They have the same pitch of 0.5 mm. The number of divisions on their circular scale is 100. The contributions to the maximum probable error of the Y measurementa)due to the errors in the measurements of d and l are the same.b)due to the error in the measurement of d is twice that due to the error in the measurement of l .c)due to the error in the measurement of l is twice that due to the error in the measurement of d.d)due to the error in the measurement of d is four times that due to the error in the measurement of l.Correct answer is option 'A'. Can you explain this answer?, a detailed solution for In the determination of Young’s modulus using Searle’s method, a wire of length L = 2 m and diameter d = 0.5 mm is used. For a load M = 2.5 kg, an extension l = 0.25 mm in the length of the wire is observed. Quantities d and l are measured using a screw gauge and a micrometer, respectively. They have the same pitch of 0.5 mm. The number of divisions on their circular scale is 100. The contributions to the maximum probable error of the Y measurementa)due to the errors in the measurements of d and l are the same.b)due to the error in the measurement of d is twice that due to the error in the measurement of l .c)due to the error in the measurement of l is twice that due to the error in the measurement of d.d)due to the error in the measurement of d is four times that due to the error in the measurement of l.Correct answer is option 'A'. Can you explain this answer? has been provided alongside types of In the determination of Young’s modulus using Searle’s method, a wire of length L = 2 m and diameter d = 0.5 mm is used. For a load M = 2.5 kg, an extension l = 0.25 mm in the length of the wire is observed. Quantities d and l are measured using a screw gauge and a micrometer, respectively. They have the same pitch of 0.5 mm. The number of divisions on their circular scale is 100. The contributions to the maximum probable error of the Y measurementa)due to the errors in the measurements of d and l are the same.b)due to the error in the measurement of d is twice that due to the error in the measurement of l .c)due to the error in the measurement of l is twice that due to the error in the measurement of d.d)due to the error in the measurement of d is four times that due to the error in the measurement of l.Correct answer is option 'A'. Can you explain this answer? theory, EduRev gives you an ample number of questions to practice In the determination of Young’s modulus using Searle’s method, a wire of length L = 2 m and diameter d = 0.5 mm is used. For a load M = 2.5 kg, an extension l = 0.25 mm in the length of the wire is observed. Quantities d and l are measured using a screw gauge and a micrometer, respectively. They have the same pitch of 0.5 mm. The number of divisions on their circular scale is 100. The contributions to the maximum probable error of the Y measurementa)due to the errors in the measurements of d and l are the same.b)due to the error in the measurement of d is twice that due to the error in the measurement of l .c)due to the error in the measurement of l is twice that due to the error in the measurement of d.d)due to the error in the measurement of d is four times that due to the error in the measurement of l.Correct answer is option 'A'. Can you explain this answer? tests, examples and also practice JEE tests.