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One mole of ideal gas is allowed to expand reversibly and adiabatically from a temperature of 27°C. If the work done by the gas in the process is 3 kJ, the final temperature will be equal to (Cv = 20 J/K mol)
  • a)
    100 K 
  • b)
    450 K
  • c)
    150 K 
  • d)
    400 K
Correct answer is option 'C'. Can you explain this answer?
Verified Answer
One mole of ideal gas is allowed to expand reversibly and adiabaticall...
w = nCv ΔT
⇒ –3 × 1000 = 1 × 20 × (T – 300)
T = 150 K
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One mole of ideal gas is allowed to expand reversibly and adiabatically from a temperature of 27°C. If the work done by the gas in the process is 3 kJ, the final temperature will be equal to (Cv= 20 J/K mol)a)100 Kb)450 Kc)150 Kd)400 KCorrect answer is option 'C'. Can you explain this answer?
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