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Limiting equivalent conductance (in S cmequiv-1) of a weak monobasic acid (HA) at infinite dilution is 100 and that of its 0.01 M solution is 5 at 298K.Match the parameters given in Column I with their values in Column II and select the answer from the codes given.           
  • a)
    a
  • b)
    b
  • c)
    c
  • d)
    d
Correct answer is option 'D'. Can you explain this answer?
Verified Answer
Limiting equivalent conductance (in S cm2equiv-1) of a weak monobasic ...



∴ [A-] = Cx, x = degree of ionisation 


[A-] = Cx = 0.01 x 0.05 = 5 x 10-4 M
[H+] = Cx = 5 x 10-4 M
pH = - log [H+]
= 4.log 5 = 3.3
By Ostwald's dilution law
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Limiting equivalent conductance (in S cm2equiv-1) of a weak monobasic acid (HA)at infinite dilution is 100 and that of its 0.01 M solution is 5 at 298K.Match the parameters given in Column I with their values in Column II and select the answer from the codes given. a)ab)bc)cd)dCorrect answer is option 'D'. Can you explain this answer?
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Limiting equivalent conductance (in S cm2equiv-1) of a weak monobasic acid (HA)at infinite dilution is 100 and that of its 0.01 M solution is 5 at 298K.Match the parameters given in Column I with their values in Column II and select the answer from the codes given. a)ab)bc)cd)dCorrect answer is option 'D'. Can you explain this answer? for Class 12 2024 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about Limiting equivalent conductance (in S cm2equiv-1) of a weak monobasic acid (HA)at infinite dilution is 100 and that of its 0.01 M solution is 5 at 298K.Match the parameters given in Column I with their values in Column II and select the answer from the codes given. a)ab)bc)cd)dCorrect answer is option 'D'. Can you explain this answer? covers all topics & solutions for Class 12 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Limiting equivalent conductance (in S cm2equiv-1) of a weak monobasic acid (HA)at infinite dilution is 100 and that of its 0.01 M solution is 5 at 298K.Match the parameters given in Column I with their values in Column II and select the answer from the codes given. a)ab)bc)cd)dCorrect answer is option 'D'. Can you explain this answer?.
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