The ratio of thickness of plates of to transparent medium a and b is 6:4. If light takes equal time in passing through them the refractive index of B with respect to A will be?

Explore Courses UPSC Exam UPSC Test Series Free Notes EduRev Infinity

Open App

Class 12 Exam > Class 12 Questions > The ratio of thickness of plates of to transp...

Join the Discussion on the App

The ratio of thickness of plates of to transparent medium a and b is 6:4. If light takes equal time in passing through them the refractive index of B with respect to A will be?

Join for Free

Join for Free

Most Upvoted Answer

The ratio of thickness of plates of to transparent medium a and b is 6...

Community Answer

The ratio of thickness of plates of to transparent medium a and b is 6...

**Introduction:**
In this problem, we are given the ratio of the thickness of two transparent plates, A and B, and we need to find the refractive index of B with respect to A. We are also given that light takes an equal amount of time to pass through both plates. To solve this problem, we will use the concept of optical path length and the formula for the refractive index.

**Understanding the Problem:**
1. We have two transparent plates, A and B.
2. The thickness of plate A is represented as '6x', and the thickness of plate B is represented as '4x'.
3. The time taken by light to pass through both plates is the same.

**Solution:**
1. Let's assume the speed of light in a vacuum is 'c'.
2. The refractive index of a medium is defined as the ratio of the speed of light in a vacuum to the speed of light in that medium.
3. The refractive index (n) can be calculated using the formula: n = c/v, where 'v' is the speed of light in the medium.
4. As the time taken by light to pass through both plates is the same, we can say that the optical path length is the same for both plates.
5. The optical path length is given by the product of the refractive index and the thickness of the medium. So, the optical path length for plate A is 'nA * 6x', and for plate B, it is 'nB * 4x'.
6. Since the optical path length is the same for both plates, we can write the equation: nA * 6x = nB * 4x.
7. Simplifying the equation, we get: nB/nA = 6/4 = 3/2.
8. Therefore, the refractive index of B with respect to A is 3/2.

**Conclusion:**
The refractive index of B with respect to A is 3/2. This means that the speed of light in medium B is one and a half times the speed of light in medium A.

Share via Whatsapp

View all answers Start learning for free

Explore Courses for Class 12 exam

Similar Class 12 Doubts

Read the following text and answer the following questions on the basis of the same:Negative Refractive Index: One of the most fundamental phenomena in optics is refraction. When a beam of light crosses the interface between two different materials, its path is altered depending on the difference in the refractive indices of the materials. The greater the difference, the greater the refraction of the beam. For all known naturally occurring materials the refractive index assumes only positive values. But does this have to be the case?In 1967, Soviet physicist Victor Veselago hypothesized that a material with a negative refractive index could exist without violating any of the laws of physics.Veselago predicted that this remarkable material would exhibit a wide variety of new optical phenomena. However, until recently no one had found such a material and Veselago’s ideas had remained untested. Recently, meta-material samples are being tested for negative refractive index. But the experiments show significant losses and this could be an intrinsic property of negativeindex materials.Snell’s law is satisfied for the materials having a negative refractive index, but the direction of the refracted light ray is ‘mirror-imaged’ about the normal to the surface.There will be an interesting difference in image formation if a vessel is filled with “negative water” having refractive index – 1.33 instead of regular water having refractive index 1.33.Say, there is a fish in a vessel filled with negative water. The position of the fish is such that the observer cannot see it due to normal refraction since the refracted ray does not reach to his eye.But due to negative refraction, he will be able to see it since the refracted ray now reaches his eye.Q. When the angle of incidence will be equal to angle of refraction for material having negative refraction index?

View answer

Read the following text and answer the following questions on the basis of the same:Negative Refractive Index: One of the most fundamental phenomena in optics is refraction. When a beam of light crosses the interface between two different materials, its path is altered depending on the difference in the refractive indices of the materials. The greater the difference, the greater the refraction of the beam. For all known naturally occurring materials the refractive index assumes only positive values. But does this have to be the case?In 1967, Soviet physicist Victor Veselago hypothesized that a material with a negative refractive index could exist without violating any of the laws of physics.Veselago predicted that this remarkable material would exhibit a wide variety of new optical phenomena. However, until recently no one had found such a material and Veselago’s ideas had remained untested. Recently, meta-material samples are being tested for negative refractive index. But the experiments show significant losses and this could be an intrinsic property of negativeindex materials.Snell’s law is satisfied for the materials having a negative refractive index, but the direction of the refracted light ray is ‘mirror-imaged’ about the normal to the surface.There will be an interesting difference in image formation if a vessel is filled with “negative water” having refractive index – 1.33 instead of regular water having refractive index 1.33.Say, there is a fish in a vessel filled with negative water. The position of the fish is such that the observer cannot see it due to normal refraction since the refracted ray does not reach to his eye.But due to negative refraction, he will be able to see it since the refracted ray now reaches his eye.Q. Which of the following is the intrinsic property of negative-index materials?

View answer

Read the following text and answer the following questions on the basis of the same:Negative Refractive Index: One of the most fundamental phenomena in optics is refraction. When a beam of light crosses the interface between two different materials, its path is altered depending on the difference in the refractive indices of the materials. The greater the difference, the greater the refraction of the beam. For all known naturally occurring materials the refractive index assumes only positive values. But does this have to be the case?In 1967, Soviet physicist Victor Veselago hypothesized that a material with a negative refractive index could exist without violating any of the laws of physics.Veselago predicted that this remarkable material would exhibit a wide variety of new optical phenomena. However, until recently no one had found such a material and Veselago’s ideas had remained untested. Recently, meta-material samples are being tested for negative refractive index. But the experiments show significant losses and this could be an intrinsic property of negativeindex materials.Snell’s law is satisfied for the materials having a negative refractive index, but the direction of the refracted light ray is ‘mirror-imaged’ about the normal to the surface.There will be an interesting difference in image formation if a vessel is filled with “negative water” having refractive index – 1.33 instead of regular water having refractive index 1.33.Say, there is a fish in a vessel filled with negative water. The position of the fish is such that the observer cannot see it due to normal refraction since the refracted ray does not reach to his eye.But due to negative refraction, he will be able to see it since the refracted ray now reaches his eye.Q. Is Snell’s law applicable for negative refraction ?

View answer

Read the following text and answer the following questions on the basis of the same:Negative Refractive Index: One of the most fundamental phenomena in optics is refraction. When a beam of light crosses the interface between two different materials, its path is altered depending on the difference in the refractive indices of the materials. The greater the difference, the greater the refraction of the beam. For all known naturally occurring materials the refractive index assumes only positive values. But does this have to be the case?In 1967, Soviet physicist Victor Veselago hypothesized that a material with a negative refractive index could exist without violating any of the laws of physics.Veselago predicted that this remarkable material would exhibit a wide variety of new optical phenomena. However, until recently no one had found such a material and Veselago’s ideas had remained untested. Recently, meta-material samples are being tested for negative refractive index. But the experiments show significant losses and this could be an intrinsic property of negativeindex materials.Snell’s law is satisfied for the materials having a negative refractive index, but the direction of the refracted light ray is ‘mirror-imaged’ about the normal to the surface.There will be an interesting difference in image formation if a vessel is filled with “negative water” having refractive index – 1.33 instead of regular water having refractive index 1.33.Say, there is a fish in a vessel filled with negative water. The position of the fish is such that the observer cannot see it due to normal refraction since the refracted ray does not reach to his eye.But due to negative refraction, he will be able to see it since the refracted ray now reaches his eye.Q. A ray incident on normal glass and “negative glass” at an angle 60°. If the magnitude of angle of refraction in normal glass is 45° then, what will be the magnitude of angle of refraction in the “negative glass”?

View answer

Read the following text and answer the following questions on the basis of the same:Negative Refractive Index: One of the most fundamental phenomena in optics is refraction. When a beam of light crosses the interface between two different materials, its path is altered depending on the difference in the refractive indices of the materials. The greater the difference, the greater the refraction of the beam. For all known naturally occurring materials the refractive index assumes only positive values. But does this have to be the case?In 1967, Soviet physicist Victor Veselago hypothesized that a material with a negative refractive index could exist without violating any of the laws of physics.Veselago predicted that this remarkable material would exhibit a wide variety of new optical phenomena. However, until recently no one had found such a material and Veselago’s ideas had remained untested. Recently, meta-material samples are being tested for negative refractive index. But the experiments show significant losses and this could be an intrinsic property of negativeindex materials.Snell’s law is satisfied for the materials having a negative refractive index, but the direction of the refracted light ray is ‘mirror-imaged’ about the normal to the surface.There will be an interesting difference in image formation if a vessel is filled with “negative water” having refractive index – 1.33 instead of regular water having refractive index 1.33.Say, there is a fish in a vessel filled with negative water. The position of the fish is such that the observer cannot see it due to normal refraction since the refracted ray does not reach to his eye.But due to negative refraction, he will be able to see it since the refracted ray now reaches his eye.Q. Who hypothesized that a material may have a negative refractive index ?

View answer

The ratio of thickness of plates of to transparent medium a and b is 6:4. If light takes equal time in passing through them the refractive index of B with respect to A will be?

Share with a Friend

Answer this doubt

Question Description
The ratio of thickness of plates of to transparent medium a and b is 6:4. If light takes equal time in passing through them the refractive index of B with respect to A will be? for Class 12 2024 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about The ratio of thickness of plates of to transparent medium a and b is 6:4. If light takes equal time in passing through them the refractive index of B with respect to A will be? covers all topics & solutions for Class 12 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The ratio of thickness of plates of to transparent medium a and b is 6:4. If light takes equal time in passing through them the refractive index of B with respect to A will be?.

Solutions for The ratio of thickness of plates of to transparent medium a and b is 6:4. If light takes equal time in passing through them the refractive index of B with respect to A will be? in English & in Hindi are available as part of our courses for Class 12. Download more important topics, notes, lectures and mock test series for Class 12 Exam by signing up for free.

Here you can find the meaning of The ratio of thickness of plates of to transparent medium a and b is 6:4. If light takes equal time in passing through them the refractive index of B with respect to A will be? defined & explained in the simplest way possible. Besides giving the explanation of The ratio of thickness of plates of to transparent medium a and b is 6:4. If light takes equal time in passing through them the refractive index of B with respect to A will be?, a detailed solution for The ratio of thickness of plates of to transparent medium a and b is 6:4. If light takes equal time in passing through them the refractive index of B with respect to A will be? has been provided alongside types of The ratio of thickness of plates of to transparent medium a and b is 6:4. If light takes equal time in passing through them the refractive index of B with respect to A will be? theory, EduRev gives you an ample number of questions to practice The ratio of thickness of plates of to transparent medium a and b is 6:4. If light takes equal time in passing through them the refractive index of B with respect to A will be? tests, examples and also practice Class 12 tests.

Explore Courses for Class 12 exam