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A uniform cable of mass ‘M’ and length ‘L’ is placed on a horizontal surface such
that its part is hanging below the edge of the surface. To lift the hanging part of the cable upto the surface, the work done should be:
  • a)
  • b)
    nMgL
  • c)
  • d)
Correct answer is option 'C'. Can you explain this answer?
Verified Answer
A uniform cable of mass ‘M’ and length ‘L’ is ...
The resultant is the centre of mass of the part AB is shifter to top i.e. 
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A uniform cable of mass ‘M’ and length ‘L’ is placed on a horizontal surface suchthat itspart is hanging below the edge of the surface. To lift the hanging part of the cable upto the surface, the work done should be:a)b)nMgLc)d)Correct answer is option 'C'. Can you explain this answer?
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