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The following C program is executed on a Unix/Linux system:
# include < unistd.h>
int main ( )
{int i; for (i = 0; i < 10; i++) if (i % 2 = = 0) fork ( ); return 0;}
The total number of child processes created is ________.
# include < unistd.h>
int main ( )
{int i; for (i = 0; i < 10; i++) if (i % 2 = = 0) fork ( ); return 0;}
The total number of child processes created is ________.
Correct answer is '31'. Can you explain this answer?
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The following C program is executed on a Unix/Linux system:# include &...
According to given logic, child creation is successful only for 5 times between 0 to 9 (As for loop is executed for 10 times)
∴ Number of child processes = 2n -1 = 25 -1 = 31
∴ Number of child processes = 2n -1 = 25 -1 = 31
Most Upvoted Answer
The following C program is executed on a Unix/Linux system:# include &...
Explanation:
Initial Process:
- The initial process starts with i = 0 and forks a child process when i is even (i % 2 == 0).
- Thus, the first fork creates 1 child process.
First Child Process:
- The first child process created by the initial process starts with i = 1 and forks a child process when i is even.
- The second fork creates 1 child process.
Second Child Process:
- The second child process created by the initial process starts with i = 2 and forks a child process when i is even.
- The third fork creates 1 child process.
Third Child Process:
- The third child process created by the initial process starts with i = 3 and forks a child process when i is even.
- The fourth fork creates 1 child process.
Fourth Child Process:
- The fourth child process created by the initial process starts with i = 4 and forks a child process when i is even.
- The fifth fork creates 1 child process.
Fifth Child Process:
- The fifth child process created by the initial process starts with i = 5 and does not fork any child process.
Total Child Processes:
- Adding up all the child processes created by each iteration (1 + 1 + 1 + 1 + 1 + 0 + 1 + 1 + 1 + 1 + 1 + 0 + ...), we get a total of 31 child processes created.
Therefore, the total number of child processes created by the given program is 31.
Initial Process:
- The initial process starts with i = 0 and forks a child process when i is even (i % 2 == 0).
- Thus, the first fork creates 1 child process.
First Child Process:
- The first child process created by the initial process starts with i = 1 and forks a child process when i is even.
- The second fork creates 1 child process.
Second Child Process:
- The second child process created by the initial process starts with i = 2 and forks a child process when i is even.
- The third fork creates 1 child process.
Third Child Process:
- The third child process created by the initial process starts with i = 3 and forks a child process when i is even.
- The fourth fork creates 1 child process.
Fourth Child Process:
- The fourth child process created by the initial process starts with i = 4 and forks a child process when i is even.
- The fifth fork creates 1 child process.
Fifth Child Process:
- The fifth child process created by the initial process starts with i = 5 and does not fork any child process.
Total Child Processes:
- Adding up all the child processes created by each iteration (1 + 1 + 1 + 1 + 1 + 0 + 1 + 1 + 1 + 1 + 1 + 0 + ...), we get a total of 31 child processes created.
Therefore, the total number of child processes created by the given program is 31.
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The following C program is executed on a Unix/Linux system:# include < unistd.h>int main ( ){int i; for (i = 0; i < 10; i++) if (i % 2 = = 0) fork ( ); return 0;}The total number of child processes created is ________.Correct answer is '31'. Can you explain this answer?
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