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A secondary amine cannot be prepared directly by
  • a)
    reduction of amide
  • b)
    reduction of cyanide
  • c)
    reduction of imine
  • d)
    reduction of isocyanide
Correct answer is option 'B'. Can you explain this answer?
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Verified Answer
A secondary amine cannot be prepared directly bya)reduction of amideb)...
Alkyl cyanide gives primary amine on reduction.
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Most Upvoted Answer
A secondary amine cannot be prepared directly bya)reduction of amideb)...
Reduction of cyanide
The reduction of cyanide is a method used to prepare secondary amines. Cyanide (CN-) can be reduced to an intermediate called an imine, which can then be further reduced to form a secondary amine. Therefore, the correct answer is not option 'B'.

Reduction of amide
The reduction of amide is a common method used to prepare amines. Amides can be reduced to primary amines by using reducing agents such as lithium aluminum hydride (LiAlH4) or sodium borohydride (NaBH4). Primary amines can further react to form secondary amines through various methods such as reductive amination.

Reduction of imine
The reduction of imine is another method to prepare secondary amines. Imine is an organic compound that contains a carbon-nitrogen double bond. It can be reduced by using reducing agents such as sodium borohydride or hydrogen gas in the presence of a metal catalyst to form a secondary amine.

Reduction of isocyanide
The reduction of isocyanide is a method used to prepare primary amines. Isocyanides can be reduced by using reducing agents such as lithium aluminum hydride or sodium borohydride to form primary amines.

Conclusion
Therefore, the correct answer is option 'B' because the reduction of cyanide can indeed be used to prepare secondary amines. The reduction of amide, imine, and isocyanide can also be used to prepare amines, but the question specifically asks for the method that cannot be used to prepare secondary amines.
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Read the passage given below and answer the following questions:Reductive alkylation is the term applied to the process of introducing alkyl groups into ammonia or a primary or secondary amine by means of an aldehyde or ketone in the presence of a reducing agent. The present discussion is limited to those reductive alkylations in which the reducing agent is hydrogen and a catalyst or "nascent" hydrogen, usually from a metalacid combination; most of these reductive alkylations have been carried out with hydrogen and a catalyst. The principal variation excluded is that in which the reducing agent is formic acid or one of its derivatives; this modification is known as the Leuckart reaction. The process of reductive alkylation of ammonia consists in the addition of ammonia to a carbonyl compound and reduction of the addition compound or its dehydration product. The reaction usually is carried out in ethanol solution when the reduction is to be effected catalytically:Since the primary amine is formed in the presence of the aldehyde it may react in the same way as ammonia, yielding an additional compound, a Schiff's base (RCH= NCH2R) and finally, a secondary amine. Similarly, the primary amine may react with the imine, forming an addition product which also is reduced to a secondary amine Finally, the secondary amine may react with either the aldehyde or the imine to give products which are reduced to tertiary amines.Similar reactions may occur when the carbonyl compound employed is a ketone.Q. The reaction of ammonia and its derivatives with aldehydes is called

A secondary amine cannot be prepared directly bya)reduction of amideb)reduction of cyanidec)reduction of imined)reduction of isocyanideCorrect answer is option 'B'. Can you explain this answer?
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