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If sin a sin b =3/10 and cos a cos b =2/5 then sin (a b) is?
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If sin a sin b =3/10 and cos a cos b =2/5 then sin (a b) is?
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If sin a sin b =3/10 and cos a cos b =2/5 then sin (a b) is?
Solution:

Given:
\[
\sin a \cdot \sin b = \frac{3}{10} \quad \text{and} \quad \cos a \cdot \cos b = \frac{2}{5}
\]

Finding sin(ab):
To find \(\sin(ab)\), we will use the trigonometric identity:
\[
\sin(a+b) = \sin a \cdot \cos b + \cos a \cdot \sin b
\]

Using the given values:
Substitute the given values into the formula:
\[
\sin(ab) = \sin a \cdot \cos b + \cos a \cdot \sin b = \frac{3}{10} + \frac{2}{5}
\]

Calculating the value:
\[
\sin(ab) = \frac{3}{10} + \frac{4}{10} = \frac{7}{10}
\]
Therefore, \(\sin(ab) = \frac{7}{10}\).
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