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The work done in increasing potential difference across the plates of capacitor from 4 to 60 is w?
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The work done in increasing potential difference across the plates of ...
Work done = Charge � Potential Difference = w = q( 6-4 ) = 2q  , so q = w/2

Now , Further change in potential = w' = q(8-6)= q X 2 = w/2 ​X 2 = w
So , workdone is same , w = w'
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The work done in increasing potential difference across the plates of capacitor from 4 to 60 is w?
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