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An upright object is placed at a distance of 40 cm in front of a convergent lens of focal length 20 cm. A convergent mirror of focal length 10 cm is placed at a distance of 60 cm on the other side of the lens. The position and size of the final image will be:
  • a)
    40cm from the convergent lens, twice the size of the object
  • b)
    40cm from the convergent mirror, same size as the object
  • c)
    20cm from the convergent mirror, twice the size of the object
  • d)
    20cm from the convergent mirror, same size as the object
Correct answer is option 'D'. Can you explain this answer?
Verified Answer
An upright object is placed at a distance of 40 cm in front of a conve...
Actual final image (3rd image) is formed at object itself with same size but according to the options best answer is taken for second image.
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The ciliary muscles of eye control the curvature of the lens in the eye and hence can alter the effective focal length of the system. When the muscles are fully relaxed, the focal length is maximum. When the muscles are strained the curvature of lens increases (that means radius of curvature decreases) and focal length decreases. For a clear vision the image must be on retina. The image distance is therefore fixed for clear vision and it equals the distance of retina from eye-lens. It is about 2.5 cm for a grown-up person.A person can theoretically have clear vision of objects situated at any large distance from the eye. The smallest distance at which a person can clearly see is related to minimum possible focal length. The ciliary muscles are most strained in this position. For an average grown-up person minimum distance of object should be around 25 cm.A person suffering from eye defects uses spectacles (Eye glass). The function of the lens of spectacles is to form the image of the objects within the range in which person can see clearly. The image of the spectacle-lens becomes object for eye-lens and whose image is formed on retina.The number of spectacle-lens used for the remedy of eye defect is decided by the power of the lens required and the number of spectacle-lens is equal to the numerical value of the power of lens with sign. For example power of lens required is +3D (converging lens of focal length 100/3 cm) then number of lens will be +3.For all the calculations required you can use the lens formula and lens makers formula. Assume that the eye lens is equiconvex lens. Neglect the distance between eye lens and the spectacle lens.Q.A nearsighted man can clearly see object only upto a distance of 100 cm and not beyond this. The number of the spectacles lens necessary for the remedy of this defect will be.

The ciliary muscles of eye control the curvature of the lens in the eye and hence can alter the effective focal length of the system. When the muscles are fully relaxed, the focal length is maximum. When the muscles are strained the curvature of lens increases (that means radius of curvature decreases) and focal length decreases. For a clear vision the image must be on retina. The image distance is therefore fixed for clear vision and it equals the distance of retina from eye-lens. It is about 2.5 cm for a grown-up person.A person can theoretically have clear vision of objects situated at any large distance from the eye. The smallest distance at which a person can clearly see is related to minimum possible focal length. The ciliary muscles are most strained in this position. For an average grown-up person minimum distance of object should be around 25 cm.A person suffering from eye defects uses spectacles (Eye glass). The function of the lens of spectacles is to form the image of the objects within the range in which person can see clearly. The image of the spectacle-lens becomes object for eye-lens and whose image is formed on retina.The number of spectacle-lens used for the remedy of eye defect is decided by the power of the lens required and the number of spectacle-lens is equal to the numerical value of the power of lens with sign. For example power of lens required is +3D (converging lens of focal length 100/3 cm) then number of lens will be +3.For all the calculations required you can use the lens formula and lens makers formula. Assume that the eye lens is equiconvex lens. Neglect the distance between eye lens and the spectacle lens.Q.Maximum focal length of eye lens of normal person is

The ciliary muscles of eye control the curvature of the lens in the eye and hence can alter the effective focal length of the system. When the muscles are fully relaxed, the focal length is maximum. When the muscles are strained the curvature of lens increases (that means radius of curvature decreases) and focal length decreases. For a clear vision the image must be on retina. The image distance is therefore fixed for clear vision and it equals the distance of retina from eye-lens. It is about 2.5 cm for a grown-up person.A person can theoretically have clear vision of objects situated at any large distance from the eye. The smallest distance at which a person can clearly see is related to minimum possible focal length. The ciliary muscles are most strained in this position. For an average grown-up person minimum distance of object should be around 25 cm.A person suffering from eye defects uses spectacles (Eye glass). The function of the lens of spectacles is to form the image of the objects within the range in which person can see clearly. The image of the spectacle-lens becomes object for eye-lens and whose image is formed on retina.The number of spectacle-lens used for the remedy of eye defect is decided by the power of the lens required and the number of spectacle-lens is equal to the numerical value of the power of lens with sign. For example power of lens required is +3D (converging lens of focal length100/3 cm) then number of lens will be +3.For all the calculations required you can use the lens formula and lens makers formula. Assume that the eye lens is equiconvex lens. Neglect the distance between eye lens and the spectacle lens.Q.Minimum focal length of eye lens of a normal person is

An upright object is placed at a distance of 40 cm in front of a convergent lens of focal length 20 cm. A convergent mirror of focal length 10 cm is placed at a distance of 60 cm on the other side of the lens. The position and size of the final image will be:a)40cm from the convergent lens, twice the size of the objectb)40cm from the convergent mirror, same size as the objectc)20cm from the convergent mirror, twice the size of the objectd)20cm from the convergent mirror, same size as the objectCorrect answer is option 'D'. Can you explain this answer?
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An upright object is placed at a distance of 40 cm in front of a convergent lens of focal length 20 cm. A convergent mirror of focal length 10 cm is placed at a distance of 60 cm on the other side of the lens. The position and size of the final image will be:a)40cm from the convergent lens, twice the size of the objectb)40cm from the convergent mirror, same size as the objectc)20cm from the convergent mirror, twice the size of the objectd)20cm from the convergent mirror, same size as the objectCorrect answer is option 'D'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about An upright object is placed at a distance of 40 cm in front of a convergent lens of focal length 20 cm. A convergent mirror of focal length 10 cm is placed at a distance of 60 cm on the other side of the lens. The position and size of the final image will be:a)40cm from the convergent lens, twice the size of the objectb)40cm from the convergent mirror, same size as the objectc)20cm from the convergent mirror, twice the size of the objectd)20cm from the convergent mirror, same size as the objectCorrect answer is option 'D'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for An upright object is placed at a distance of 40 cm in front of a convergent lens of focal length 20 cm. A convergent mirror of focal length 10 cm is placed at a distance of 60 cm on the other side of the lens. The position and size of the final image will be:a)40cm from the convergent lens, twice the size of the objectb)40cm from the convergent mirror, same size as the objectc)20cm from the convergent mirror, twice the size of the objectd)20cm from the convergent mirror, same size as the objectCorrect answer is option 'D'. Can you explain this answer?.
Solutions for An upright object is placed at a distance of 40 cm in front of a convergent lens of focal length 20 cm. A convergent mirror of focal length 10 cm is placed at a distance of 60 cm on the other side of the lens. The position and size of the final image will be:a)40cm from the convergent lens, twice the size of the objectb)40cm from the convergent mirror, same size as the objectc)20cm from the convergent mirror, twice the size of the objectd)20cm from the convergent mirror, same size as the objectCorrect answer is option 'D'. Can you explain this answer? in English & in Hindi are available as part of our courses for JEE. Download more important topics, notes, lectures and mock test series for JEE Exam by signing up for free.
Here you can find the meaning of An upright object is placed at a distance of 40 cm in front of a convergent lens of focal length 20 cm. A convergent mirror of focal length 10 cm is placed at a distance of 60 cm on the other side of the lens. The position and size of the final image will be:a)40cm from the convergent lens, twice the size of the objectb)40cm from the convergent mirror, same size as the objectc)20cm from the convergent mirror, twice the size of the objectd)20cm from the convergent mirror, same size as the objectCorrect answer is option 'D'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of An upright object is placed at a distance of 40 cm in front of a convergent lens of focal length 20 cm. A convergent mirror of focal length 10 cm is placed at a distance of 60 cm on the other side of the lens. The position and size of the final image will be:a)40cm from the convergent lens, twice the size of the objectb)40cm from the convergent mirror, same size as the objectc)20cm from the convergent mirror, twice the size of the objectd)20cm from the convergent mirror, same size as the objectCorrect answer is option 'D'. Can you explain this answer?, a detailed solution for An upright object is placed at a distance of 40 cm in front of a convergent lens of focal length 20 cm. A convergent mirror of focal length 10 cm is placed at a distance of 60 cm on the other side of the lens. The position and size of the final image will be:a)40cm from the convergent lens, twice the size of the objectb)40cm from the convergent mirror, same size as the objectc)20cm from the convergent mirror, twice the size of the objectd)20cm from the convergent mirror, same size as the objectCorrect answer is option 'D'. Can you explain this answer? has been provided alongside types of An upright object is placed at a distance of 40 cm in front of a convergent lens of focal length 20 cm. A convergent mirror of focal length 10 cm is placed at a distance of 60 cm on the other side of the lens. The position and size of the final image will be:a)40cm from the convergent lens, twice the size of the objectb)40cm from the convergent mirror, same size as the objectc)20cm from the convergent mirror, twice the size of the objectd)20cm from the convergent mirror, same size as the objectCorrect answer is option 'D'. Can you explain this answer? theory, EduRev gives you an ample number of questions to practice An upright object is placed at a distance of 40 cm in front of a convergent lens of focal length 20 cm. A convergent mirror of focal length 10 cm is placed at a distance of 60 cm on the other side of the lens. The position and size of the final image will be:a)40cm from the convergent lens, twice the size of the objectb)40cm from the convergent mirror, same size as the objectc)20cm from the convergent mirror, twice the size of the objectd)20cm from the convergent mirror, same size as the objectCorrect answer is option 'D'. Can you explain this answer? tests, examples and also practice JEE tests.
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