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A car starts from rest and accelerates uniformly to a speed of 50 m/s over distance of 250 m find the acceleration and time taken by the car to cover this distance?
Most Upvoted Answer
A car starts from rest and accelerates uniformly to a speed of 50 m/s ...
Given data:
- Initial velocity (u) = 0 m/s
- Final velocity (v) = 50 m/s
- Distance (s) = 250 m

Finding Acceleration:
- Using the equation of motion: \(v^2 = u^2 + 2as\), where a is the acceleration
- Plug in the values: \(50^2 = 0 + 2a(250)\)
- Solve for acceleration: \(a = \frac{50^2}{2 \times 250} = 5 \, m/s^2\)

Finding Time Taken:
- Using the equation of motion: \(v = u + at\), where t is the time taken
- Plug in the values: \(50 = 0 + 5t\)
- Solve for time: \(t = \frac{50}{5} = 10 \, seconds\)
Therefore, the acceleration of the car is 5 m/s² and the time taken to cover the distance of 250 m is 10 seconds. The car accelerates uniformly from rest to a speed of 50 m/s over the given distance.
Community Answer
A car starts from rest and accelerates uniformly to a speed of 50 m/s ...
Acceleration= 5m/sec square, time taken =10 sec
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A car starts from rest and accelerates uniformly to a speed of 50 m/s over distance of 250 m find the acceleration and time taken by the car to cover this distance?
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A car starts from rest and accelerates uniformly to a speed of 50 m/s over distance of 250 m find the acceleration and time taken by the car to cover this distance? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about A car starts from rest and accelerates uniformly to a speed of 50 m/s over distance of 250 m find the acceleration and time taken by the car to cover this distance? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A car starts from rest and accelerates uniformly to a speed of 50 m/s over distance of 250 m find the acceleration and time taken by the car to cover this distance?.
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