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Vijay started from school and walked 2 Km straight towards South. He then turned left and travelled 3 Km. He then again turned left and travelled 2 km straight. How far is he from his school ?
- a)3 Km
- b)4 Km
- c)5 Km
- d)6 Km
Correct answer is option 'A'. Can you explain this answer?
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Verified Answer
Vijay started from school and walked 2 Km straight towards South. He t...
O and C are initial and final positions of Vijay. Clearly, OC = AB = 3 Km
Most Upvoted Answer
Vijay started from school and walked 2 Km straight towards South. He t...
Given Information:
- Vijay starts from school and walks 2 km straight towards the south.
- He turns left and travels 3 km.
- He turns left again and travels 2 km straight.
To Find:
The distance Vijay is from his school.
Solution:
When Vijay starts from his school, we can assume his starting point as the origin (0,0) on a coordinate plane. Let's visualize his movements step by step.
Step 1:
Vijay walks 2 km straight towards the south. This means he moves downwards on the y-axis by 2 km.
Step 2:
Vijay turns left and travels 3 km. Since he turns left from the south direction, he now moves towards the east on the x-axis by 3 km.
Step 3:
Vijay turns left again and travels 2 km straight. This means he moves upwards on the y-axis by 2 km.
Final Position:
After completing these steps, Vijay's final position can be represented as (3, 0) on the coordinate plane.
Distance from School:
To find the distance between Vijay's final position and his school (origin), we can use the distance formula (Pythagorean theorem).
The distance is given by:
distance = √[(x2 - x1)^2 + (y2 - y1)^2]
Plugging in the values:
distance = √[(3 - 0)^2 + (0 - 0)^2]
distance = √(9 + 0)
distance = √9
distance = 3 km
Therefore, Vijay is 3 km away from his school.
Answer:
The correct answer is option A) 3 km.
- Vijay starts from school and walks 2 km straight towards the south.
- He turns left and travels 3 km.
- He turns left again and travels 2 km straight.
To Find:
The distance Vijay is from his school.
Solution:
When Vijay starts from his school, we can assume his starting point as the origin (0,0) on a coordinate plane. Let's visualize his movements step by step.
Step 1:
Vijay walks 2 km straight towards the south. This means he moves downwards on the y-axis by 2 km.
Step 2:
Vijay turns left and travels 3 km. Since he turns left from the south direction, he now moves towards the east on the x-axis by 3 km.
Step 3:
Vijay turns left again and travels 2 km straight. This means he moves upwards on the y-axis by 2 km.
Final Position:
After completing these steps, Vijay's final position can be represented as (3, 0) on the coordinate plane.
Distance from School:
To find the distance between Vijay's final position and his school (origin), we can use the distance formula (Pythagorean theorem).
The distance is given by:
distance = √[(x2 - x1)^2 + (y2 - y1)^2]
Plugging in the values:
distance = √[(3 - 0)^2 + (0 - 0)^2]
distance = √(9 + 0)
distance = √9
distance = 3 km
Therefore, Vijay is 3 km away from his school.
Answer:
The correct answer is option A) 3 km.
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Vijay started from school and walked 2 Km straight towards South. He then turned left and travelled 3 Km. He then again turned left and travelled 2 km straight. How far is he from his school ?a)3 Kmb)4 Kmc)5 Kmd)6 KmCorrect answer is option 'A'. Can you explain this answer?
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