CO2 + C---->2CO

Understanding the Reaction
When a mixture of CO2 (carbon dioxide) and CO (carbon monoxide) passes through hot coke, a reduction reaction occurs. The coke, primarily carbon, reduces CO2 to CO. The general reaction is:
- CO2 + C → 2CO
This indicates that for every mole of CO2, two moles of CO are produced.
Initial and Final Volumes
Let’s denote the original volume of CO2 as "x" and the volume of CO as "y".
- The total initial volume (V_initial) = x + y
After passing through hot coke, the volume of the gases increases by 20%. Thus:
- V_final = V_initial + 20% of V_initial
- V_final = 1.2 * V_initial
Volume Change Calculation
1. The volume of CO2 converted into CO will reduce the volume of CO2 while increasing the volume of CO.
2. The new volume after the reaction can be represented as:
- V_final = (x - z) + (y + 2z)
- Where "z" is the volume of CO2 that has reacted.
3. This simplifies to:
- V_final = (x + y + z)
4. Since we know V_final = 1.2 * (x + y), we can equate:
- x + y + z = 1.2 * (x + y)
Expressing in Terms of z
From the equation, we deduce:
- z = 0.2 * (x + y)
This means that 20% of the total initial volume of CO2 has reacted to form additional CO.
Finding the Percentage of CO2
To find the percentage of CO2 in the original sample, consider:
- The volume of CO2 that remains = x - z = x - 0.2(x + y)
Now, calculating the percentage of CO2 in the original sample:
- % CO2 = [(x - 0.2(x + y)) / (x + y)] * 100
Solving this will yield the desired percentage of CO2 in the original sample.