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The temperature, at which the root mean square velocity of hydrogen molecules equals their escape velocity from the earth, is closest to:[Boltzmann Constant kB =1.38 X 10–23 J/K Avogadro Number NA = 6.02 X 1026 /kg Radius of Earth : 6.4 X 106 mGravitational acceleration on Earth = 10 ms–2]a)650 Kb)104 Kc)3 X 105 Kd)800 KCorrect answer is option 'B'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared
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the JEE exam syllabus. Information about The temperature, at which the root mean square velocity of hydrogen molecules equals their escape velocity from the earth, is closest to:[Boltzmann Constant kB =1.38 X 10–23 J/K Avogadro Number NA = 6.02 X 1026 /kg Radius of Earth : 6.4 X 106 mGravitational acceleration on Earth = 10 ms–2]a)650 Kb)104 Kc)3 X 105 Kd)800 KCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam.
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Here you can find the meaning of The temperature, at which the root mean square velocity of hydrogen molecules equals their escape velocity from the earth, is closest to:[Boltzmann Constant kB =1.38 X 10–23 J/K Avogadro Number NA = 6.02 X 1026 /kg Radius of Earth : 6.4 X 106 mGravitational acceleration on Earth = 10 ms–2]a)650 Kb)104 Kc)3 X 105 Kd)800 KCorrect answer is option 'B'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of
The temperature, at which the root mean square velocity of hydrogen molecules equals their escape velocity from the earth, is closest to:[Boltzmann Constant kB =1.38 X 10–23 J/K Avogadro Number NA = 6.02 X 1026 /kg Radius of Earth : 6.4 X 106 mGravitational acceleration on Earth = 10 ms–2]a)650 Kb)104 Kc)3 X 105 Kd)800 KCorrect answer is option 'B'. Can you explain this answer?, a detailed solution for The temperature, at which the root mean square velocity of hydrogen molecules equals their escape velocity from the earth, is closest to:[Boltzmann Constant kB =1.38 X 10–23 J/K Avogadro Number NA = 6.02 X 1026 /kg Radius of Earth : 6.4 X 106 mGravitational acceleration on Earth = 10 ms–2]a)650 Kb)104 Kc)3 X 105 Kd)800 KCorrect answer is option 'B'. Can you explain this answer? has been provided alongside types of The temperature, at which the root mean square velocity of hydrogen molecules equals their escape velocity from the earth, is closest to:[Boltzmann Constant kB =1.38 X 10–23 J/K Avogadro Number NA = 6.02 X 1026 /kg Radius of Earth : 6.4 X 106 mGravitational acceleration on Earth = 10 ms–2]a)650 Kb)104 Kc)3 X 105 Kd)800 KCorrect answer is option 'B'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice The temperature, at which the root mean square velocity of hydrogen molecules equals their escape velocity from the earth, is closest to:[Boltzmann Constant kB =1.38 X 10–23 J/K Avogadro Number NA = 6.02 X 1026 /kg Radius of Earth : 6.4 X 106 mGravitational acceleration on Earth = 10 ms–2]a)650 Kb)104 Kc)3 X 105 Kd)800 KCorrect answer is option 'B'. Can you explain this answer? tests, examples and also practice JEE tests.