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To measure the quantity of MnCl2 dissolved in an aqueous solution, it was completely converted to KMnO4using the reaction, MnCl2 + K2S2O8 + H2O -->KMnO4 + H2SO4 + HCl (equation not balanced). Few dropsof concentrated HCl were added to this solution and gently warmed. Further, oxalic acid (225 mg) wasadded in portions till the colour of the permanganate ion disappeared. The quantity of MnCl2 (in mg)present in the initial solution is ____.(Atomic weights in g mol−1: Mn = 55, Cl = 35.5)a)b)c)d)Correct answer is '126'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared
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the JEE exam syllabus. Information about To measure the quantity of MnCl2 dissolved in an aqueous solution, it was completely converted to KMnO4using the reaction, MnCl2 + K2S2O8 + H2O -->KMnO4 + H2SO4 + HCl (equation not balanced). Few dropsof concentrated HCl were added to this solution and gently warmed. Further, oxalic acid (225 mg) wasadded in portions till the colour of the permanganate ion disappeared. The quantity of MnCl2 (in mg)present in the initial solution is ____.(Atomic weights in g mol−1: Mn = 55, Cl = 35.5)a)b)c)d)Correct answer is '126'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam.
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Here you can find the meaning of To measure the quantity of MnCl2 dissolved in an aqueous solution, it was completely converted to KMnO4using the reaction, MnCl2 + K2S2O8 + H2O -->KMnO4 + H2SO4 + HCl (equation not balanced). Few dropsof concentrated HCl were added to this solution and gently warmed. Further, oxalic acid (225 mg) wasadded in portions till the colour of the permanganate ion disappeared. The quantity of MnCl2 (in mg)present in the initial solution is ____.(Atomic weights in g mol−1: Mn = 55, Cl = 35.5)a)b)c)d)Correct answer is '126'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of
To measure the quantity of MnCl2 dissolved in an aqueous solution, it was completely converted to KMnO4using the reaction, MnCl2 + K2S2O8 + H2O -->KMnO4 + H2SO4 + HCl (equation not balanced). Few dropsof concentrated HCl were added to this solution and gently warmed. Further, oxalic acid (225 mg) wasadded in portions till the colour of the permanganate ion disappeared. The quantity of MnCl2 (in mg)present in the initial solution is ____.(Atomic weights in g mol−1: Mn = 55, Cl = 35.5)a)b)c)d)Correct answer is '126'. Can you explain this answer?, a detailed solution for To measure the quantity of MnCl2 dissolved in an aqueous solution, it was completely converted to KMnO4using the reaction, MnCl2 + K2S2O8 + H2O -->KMnO4 + H2SO4 + HCl (equation not balanced). Few dropsof concentrated HCl were added to this solution and gently warmed. Further, oxalic acid (225 mg) wasadded in portions till the colour of the permanganate ion disappeared. The quantity of MnCl2 (in mg)present in the initial solution is ____.(Atomic weights in g mol−1: Mn = 55, Cl = 35.5)a)b)c)d)Correct answer is '126'. Can you explain this answer? has been provided alongside types of To measure the quantity of MnCl2 dissolved in an aqueous solution, it was completely converted to KMnO4using the reaction, MnCl2 + K2S2O8 + H2O -->KMnO4 + H2SO4 + HCl (equation not balanced). Few dropsof concentrated HCl were added to this solution and gently warmed. Further, oxalic acid (225 mg) wasadded in portions till the colour of the permanganate ion disappeared. The quantity of MnCl2 (in mg)present in the initial solution is ____.(Atomic weights in g mol−1: Mn = 55, Cl = 35.5)a)b)c)d)Correct answer is '126'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice To measure the quantity of MnCl2 dissolved in an aqueous solution, it was completely converted to KMnO4using the reaction, MnCl2 + K2S2O8 + H2O -->KMnO4 + H2SO4 + HCl (equation not balanced). Few dropsof concentrated HCl were added to this solution and gently warmed. Further, oxalic acid (225 mg) wasadded in portions till the colour of the permanganate ion disappeared. The quantity of MnCl2 (in mg)present in the initial solution is ____.(Atomic weights in g mol−1: Mn = 55, Cl = 35.5)a)b)c)d)Correct answer is '126'. Can you explain this answer? tests, examples and also practice JEE tests.