two beads A and B of equal mass m are connected by a light inextensibl...
Description of the Problem:
Two beads A and B of equal mass m are connected by a light inextensible cord and are constrained to move on a frictionless ring in a vertical plane. The blocks are released from rest, and we need to find the tension in the cord just after the release.
Analysis:
- The system consists of two masses connected by a cord, moving in a circular path.
- As the blocks are released from rest, the initial velocities of both beads are zero.
- The only force acting on each bead is tension in the cord.
Solution:
- At the instant of release, the tension in the cord provides the centripetal force required for circular motion.
- The tension in the cord can be calculated using the centripetal force formula: T = mv^2 / r, where T is the tension, m is the mass of each bead, v is the velocity, and r is the radius of the ring.
- Since the initial velocity is zero, the tension just after the release is also zero.
Conclusion:
- Just after the release, the tension in the cord is zero as there is no initial velocity to provide the centripetal force required for circular motion.
- As the beads start moving, the tension in the cord will increase to provide the centripetal force necessary to keep the beads in circular motion on the ring.
two beads A and B of equal mass m are connected by a light inextensibl...
Just after the release B moves downwards and A moves horizontally leftwards with the same acceleration say a
drawing free body diagram for both A and B
T cos 45 =ma
T=√2 ma _ (1)
mg - T cos 45 =ma
mg - ma = ma
a = g/2 _ (2)
substituting this in equation (1) we get
T = mg/√2
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