The sides of a triangle are in the ratio of 2:3:4 and its perimeter is...
Given:
The sides of a triangle are in the ratio of 2:3:4 and its perimeter is 90cm.
To find:
The area of the triangle.
Solution:
Let the sides of the triangle be 2x, 3x, and 4x.
Perimeter of the triangle = 2x + 3x + 4x = 9x
Given, the perimeter of the triangle is 90cm.
Therefore, 9x = 90cm
x = 10cm
The sides of the triangle are 2x = 20cm, 3x = 30cm, and 4x = 40cm.
We can use Heron's formula to find the area of the triangle.
Heron's formula states that the area of a triangle with sides a, b, and c is given by:
Area of triangle = √(s(s-a)(s-b)(s-c))
where s = (a+b+c)/2 is the semi-perimeter of the triangle.
Substituting the values of a, b, and c, we get:
a = 20cm, b = 30cm, and c = 40cm
s = (a+b+c)/2 = (20+30+40)/2 = 45cm
Area of triangle = √(45(45-20)(45-30)(45-40)) = √(45*25*15*5) = 562.5cm²
Therefore, the area of the triangle is 562.5cm².
The sides of a triangle are in the ratio of 2:3:4 and its perimeter is...
The area of triangle is 375 square cm
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