**Problem:**
A stone is dropped from the top of a tower and travels 24.5 m in the last second of its journey. What is the height of the tower?

**Solution:**
To find the height of the tower, we need to use the equations of motion. The motion of the stone can be divided into three stages:

1. **Stage 1: Stone falling freely**
- The stone is dropped from rest, so its initial velocity (u) is 0 m/s.
- The acceleration due to gravity (g) acts in the downward direction and is approximately 9.8 m/s^2.
- The time taken by the stone to reach the ground is unknown.
- The distance covered by the stone during this stage is also unknown.

2. **Stage 2: Stone in the last second**
- In the last second of its journey, the stone travels a distance of 24.5 m.
- We know that the time taken during this stage is 1 second.

3. **Stage 3: Stone reaches the ground**
- The stone reaches the ground with a final velocity (v) of unknown value.
- The distance covered by the stone during this stage is the same as the height of the tower.

Using the equations of motion, we can relate the distance covered, time taken, initial velocity, acceleration, and final velocity. Let's calculate the time taken for the first stage.

- Using the equation: v = u + gt
- Final velocity (v) for the first stage is 0 m/s.
- Initial velocity (u) is 0 m/s.
- Acceleration (g) is 9.8 m/s^2.

Substituting these values into the equation, we get:
0 = 0 + (9.8)t
0 = 9.8t

Therefore, t = 0 seconds.

Since the time taken for the first stage is 0 seconds, the stone travels 0 distance during this stage.

Now, let's calculate the initial velocity of the stone for the second stage.

- Using the equation: v = u + gt
- Final velocity (v) for the second stage is unknown.
- Initial velocity (u) for the second stage is also unknown.
- Acceleration (g) is 9.8 m/s^2.
- Time taken (t) for the second stage is 1 second.

Substituting these values into the equation, we get:
v = u + (9.8)(1)
v = u + 9.8

Since the stone is dropped from rest, the initial velocity (u) is 0 m/s. Therefore, we can simplify the equation to:
v = 9.8

The final velocity (v) at the end of the second stage is 9.8 m/s. This means that the stone is falling with a velocity of 9.8 m/s in the last second of its journey.

Now, let's calculate the distance covered during the first and second stages combined.

- Using the equation: s = ut + (1/2)gt^2
- Initial velocity (u) is 0 m/s.
- Acceleration (g) is 9.8 m/s^2.
- Time taken (t