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A 0.3015 g of silver nitrate when dissolved in 28.40 g of water depressed the freezing point by 0.212 ºC. To what extent is silver nitrate dissociated ? (Kf for water = 1.85 ºC mol–1)?
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A 0.3015 g of silver nitrate when dissolved in 28.40 g of water depres...
Solution:
Gathering Information:
- Mass of Silver Nitrate (AgNO3) = 0.3015 g
- Mass of Water (H2O) = 28.40 g
- Freezing Point Depression (ΔTf) = 0.212 °C
- Cryoscopic Constant (Kf) = 1.85 °C mol-1
Calculating Molality:
- Molality (m) = moles of solute (AgNO3) / mass of solvent (H2O) in kg
- Mass of solvent (H2O) = 28.40 g = 0.0284 kg
- Molar mass of AgNO3 = 107.87 + 14.01 + 3x16.00 = 169.87 g/mol
- Moles of AgNO3 = Mass / Molar mass = 0.3015 / 169.87 = 0.001774 mol
- Molality (m) = 0.001774 / 0.0284 = 0.0625 mol kg-1
Calculating Degree of Dissociation:
- Freezing Point Depression (ΔTf) = Kf x m x i
- i = van't Hoff Factor (degree of dissociation + 1)
- Substituting the values, 0.212 = 1.85 x 0.0625 x (degree of dissociation + 1)
- Solving for degree of dissociation, degree of dissociation = 0.798 or 79.8%
Explanation:
When a solute is dissolved in a solvent, the freezing point of the solvent decreases. This phenomenon is known as freezing point depression. The extent of freezing point depression depends on the molality of the solution, which is the number of moles of solute per kilogram of solvent. The degree of dissociation is a measure of how much the solute dissociates into its constituent ions when it dissolves in the solvent. In this case, we have calculated the molality of the solution and used it to calculate the degree of dissociation using the van't Hoff factor. The degree of dissociation turns out to be 79.8%, which means that 79.8% of the silver nitrate molecules dissociate into their constituent ions when they dissolve in water.
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A 0.3015 g of silver nitrate when dissolved in 28.40 g of water depressed the freezing point by 0.212 ºC. To what extent is silver nitrate dissociated ? (Kf for water = 1.85 ºC mol–1)?
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A 0.3015 g of silver nitrate when dissolved in 28.40 g of water depressed the freezing point by 0.212 ºC. To what extent is silver nitrate dissociated ? (Kf for water = 1.85 ºC mol–1)? for IIT JAM 2024 is part of IIT JAM preparation. The Question and answers have been prepared according to the IIT JAM exam syllabus. Information about A 0.3015 g of silver nitrate when dissolved in 28.40 g of water depressed the freezing point by 0.212 ºC. To what extent is silver nitrate dissociated ? (Kf for water = 1.85 ºC mol–1)? covers all topics & solutions for IIT JAM 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A 0.3015 g of silver nitrate when dissolved in 28.40 g of water depressed the freezing point by 0.212 ºC. To what extent is silver nitrate dissociated ? (Kf for water = 1.85 ºC mol–1)?.
A 0.3015 g of silver nitrate when dissolved in 28.40 g of water depressed the freezing point by 0.212 ºC. To what extent is silver nitrate dissociated ? (Kf for water = 1.85 ºC mol–1)? for IIT JAM 2024 is part of IIT JAM preparation. The Question and answers have been prepared according to the IIT JAM exam syllabus. Information about A 0.3015 g of silver nitrate when dissolved in 28.40 g of water depressed the freezing point by 0.212 ºC. To what extent is silver nitrate dissociated ? (Kf for water = 1.85 ºC mol–1)? covers all topics & solutions for IIT JAM 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A 0.3015 g of silver nitrate when dissolved in 28.40 g of water depressed the freezing point by 0.212 ºC. To what extent is silver nitrate dissociated ? (Kf for water = 1.85 ºC mol–1)?.
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