Mechanical Engineering Exam  >  Mechanical Engineering Questions  >  Heating the hypoeutectoid steels to 30oC abov... Start Learning for Free
Heating the hypoeutectoid steels to 30oC above the upper critical temperatureline, soaking at that temperature and then cooling slowly to room temperature toform a pearlite and ferrite structure, is known as 
  • a)
    Hardening
  • b)
    Normalizing
  • c)
    Tempering
  • d)
    Annealing
Correct answer is option 'D'. Can you explain this answer?
Verified Answer
Heating the hypoeutectoid steels to 30oC above the upper critical temp...
Ans. (d) The process described is annealing.
View all questions of this test
Most Upvoted Answer
Heating the hypoeutectoid steels to 30oC above the upper critical temp...
Answer:
Annealing:
Annealing is a heat treatment process that involves heating a material, in this case, hypoeutectoid steels, to a specific temperature and then slowly cooling it to room temperature. This process is carried out to alter the microstructure of the material, making it softer, more ductile, and less brittle.

The Process:
The specific process mentioned in the question involves heating the hypoeutectoid steels to 30oC above the upper critical temperatureline, soaking at that temperature, and then cooling slowly to room temperature. This process is commonly known as annealing. Let's understand each step in detail:

1. Heating: The hypoeutectoid steels are heated to a temperature that is 30oC above the upper critical temperatureline. The upper critical temperatureline is the temperature at which the steel undergoes a phase transformation and austenite is formed. By heating the steel above this temperature, all the existing microstructures are dissolved, and the steel becomes fully austenitic.

2. Soaking: Once the steel reaches the desired temperature, it is held at that temperature for a specific duration of time. This soaking time allows for the complete transformation of the microstructure and the homogenization of the material.

3. Cooling: After the soaking period, the steel is slowly cooled to room temperature. The slow cooling rate is crucial to control the formation of the desired microstructure. In this case, the cooling rate is slow enough to encourage the formation of a pearlite and ferrite structure.

4. Pearlite and Ferrite Structure: The slow cooling rate during annealing allows for the formation of a pearlite and ferrite structure. Pearlite is a lamellar structure consisting of alternating layers of ferrite and cementite. Ferrite is a relatively soft and ductile phase, while cementite is harder and more brittle. This microstructure provides a good balance between strength and ductility in the steel.

Conclusion:
Heating the hypoeutectoid steels to 30oC above the upper critical temperatureline, soaking at that temperature, and then cooling slowly to room temperature is known as annealing. This heat treatment process helps in achieving a desired microstructure that enhances the mechanical properties of the steel, making it softer, more ductile, and less brittle.
Attention Mechanical Engineering Students!
To make sure you are not studying endlessly, EduRev has designed Mechanical Engineering study material, with Structured Courses, Videos, & Test Series. Plus get personalized analysis, doubt solving and improvement plans to achieve a great score in Mechanical Engineering.
Explore Courses for Mechanical Engineering exam

Top Courses for Mechanical Engineering

Heating the hypoeutectoid steels to 30oC above the upper critical temperatureline, soaking at that temperature and then cooling slowly to room temperature toform a pearlite and ferrite structure, is known asa)Hardeningb)Normalizingc)Temperingd)AnnealingCorrect answer is option 'D'. Can you explain this answer?
Question Description
Heating the hypoeutectoid steels to 30oC above the upper critical temperatureline, soaking at that temperature and then cooling slowly to room temperature toform a pearlite and ferrite structure, is known asa)Hardeningb)Normalizingc)Temperingd)AnnealingCorrect answer is option 'D'. Can you explain this answer? for Mechanical Engineering 2024 is part of Mechanical Engineering preparation. The Question and answers have been prepared according to the Mechanical Engineering exam syllabus. Information about Heating the hypoeutectoid steels to 30oC above the upper critical temperatureline, soaking at that temperature and then cooling slowly to room temperature toform a pearlite and ferrite structure, is known asa)Hardeningb)Normalizingc)Temperingd)AnnealingCorrect answer is option 'D'. Can you explain this answer? covers all topics & solutions for Mechanical Engineering 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Heating the hypoeutectoid steels to 30oC above the upper critical temperatureline, soaking at that temperature and then cooling slowly to room temperature toform a pearlite and ferrite structure, is known asa)Hardeningb)Normalizingc)Temperingd)AnnealingCorrect answer is option 'D'. Can you explain this answer?.
Solutions for Heating the hypoeutectoid steels to 30oC above the upper critical temperatureline, soaking at that temperature and then cooling slowly to room temperature toform a pearlite and ferrite structure, is known asa)Hardeningb)Normalizingc)Temperingd)AnnealingCorrect answer is option 'D'. Can you explain this answer? in English & in Hindi are available as part of our courses for Mechanical Engineering. Download more important topics, notes, lectures and mock test series for Mechanical Engineering Exam by signing up for free.
Here you can find the meaning of Heating the hypoeutectoid steels to 30oC above the upper critical temperatureline, soaking at that temperature and then cooling slowly to room temperature toform a pearlite and ferrite structure, is known asa)Hardeningb)Normalizingc)Temperingd)AnnealingCorrect answer is option 'D'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of Heating the hypoeutectoid steels to 30oC above the upper critical temperatureline, soaking at that temperature and then cooling slowly to room temperature toform a pearlite and ferrite structure, is known asa)Hardeningb)Normalizingc)Temperingd)AnnealingCorrect answer is option 'D'. Can you explain this answer?, a detailed solution for Heating the hypoeutectoid steels to 30oC above the upper critical temperatureline, soaking at that temperature and then cooling slowly to room temperature toform a pearlite and ferrite structure, is known asa)Hardeningb)Normalizingc)Temperingd)AnnealingCorrect answer is option 'D'. Can you explain this answer? has been provided alongside types of Heating the hypoeutectoid steels to 30oC above the upper critical temperatureline, soaking at that temperature and then cooling slowly to room temperature toform a pearlite and ferrite structure, is known asa)Hardeningb)Normalizingc)Temperingd)AnnealingCorrect answer is option 'D'. Can you explain this answer? theory, EduRev gives you an ample number of questions to practice Heating the hypoeutectoid steels to 30oC above the upper critical temperatureline, soaking at that temperature and then cooling slowly to room temperature toform a pearlite and ferrite structure, is known asa)Hardeningb)Normalizingc)Temperingd)AnnealingCorrect answer is option 'D'. Can you explain this answer? tests, examples and also practice Mechanical Engineering tests.
Explore Courses for Mechanical Engineering exam

Top Courses for Mechanical Engineering

Explore Courses
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
10M+ students study on EduRev