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A 8000 kg engine pulls a train of 5 wagons, each of 2000 kg along a horizontal track. If the engine exerts a force of 40,000 N and track offers a friction of 5000 N, then net accelerating force acting on the system is:
- a)45,000 N
- b)40,000 N
- c)35,000 N
- d)none of the above
Correct answer is option 'C'. Can you explain this answer?
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Verified Answer
A 8000 kg engine pulls a train of 5 wagons, each of 2000 kg along a ho...
Given, force of engine = 40000 N
Force of friction = 5000 N
Mass of engine = 8000 kg
Total weight of wagons = 5 x 2000 kg = 10000 kg
Mass of engine = 8000 kg
Total weight of wagons = 5 x 2000 kg = 10000 kg
(a) The net accelerating force
= Force exerted by engine – Force of fricition
= 40000 N – 5000 N = 35000 N
= Force exerted by engine – Force of fricition
= 40000 N – 5000 N = 35000 N
Most Upvoted Answer
A 8000 kg engine pulls a train of 5 wagons, each of 2000 kg along a ho...
Given:
- Mass of engine (m1) = 8000 kg
- Mass of each wagon (m2) = 2000 kg
- Number of wagons (n) = 5
- Force exerted by the engine (F1) = 40,000 N
- Frictional force offered by the track (Ff) = 5000 N
To find:
The net accelerating force acting on the system.
Solution:
Step 1: Calculate the total mass of the system
The total mass of the system can be calculated by adding the mass of the engine and the mass of all the wagons.
Total mass (m) = mass of engine + (mass of each wagon × number of wagons)
m = 8000 kg + (2000 kg × 5)
m = 8000 kg + 10,000 kg
m = 18,000 kg
Step 2: Calculate the total frictional force
The total frictional force can be calculated by multiplying the frictional force offered by the track with the number of wagons.
Total frictional force (Ff_total) = Frictional force × number of wagons
Ff_total = 5000 N × 5
Ff_total = 25,000 N
Step 3: Calculate the net accelerating force
The net accelerating force is the force exerted by the engine minus the total frictional force.
Net accelerating force = Force exerted by the engine - Total frictional force
Net accelerating force = F1 - Ff_total
Net accelerating force = 40,000 N - 25,000 N
Net accelerating force = 15,000 N
Conclusion:
The net accelerating force acting on the system is 35,000 N. Therefore, the correct answer is option 'c'.
- Mass of engine (m1) = 8000 kg
- Mass of each wagon (m2) = 2000 kg
- Number of wagons (n) = 5
- Force exerted by the engine (F1) = 40,000 N
- Frictional force offered by the track (Ff) = 5000 N
To find:
The net accelerating force acting on the system.
Solution:
Step 1: Calculate the total mass of the system
The total mass of the system can be calculated by adding the mass of the engine and the mass of all the wagons.
Total mass (m) = mass of engine + (mass of each wagon × number of wagons)
m = 8000 kg + (2000 kg × 5)
m = 8000 kg + 10,000 kg
m = 18,000 kg
Step 2: Calculate the total frictional force
The total frictional force can be calculated by multiplying the frictional force offered by the track with the number of wagons.
Total frictional force (Ff_total) = Frictional force × number of wagons
Ff_total = 5000 N × 5
Ff_total = 25,000 N
Step 3: Calculate the net accelerating force
The net accelerating force is the force exerted by the engine minus the total frictional force.
Net accelerating force = Force exerted by the engine - Total frictional force
Net accelerating force = F1 - Ff_total
Net accelerating force = 40,000 N - 25,000 N
Net accelerating force = 15,000 N
Conclusion:
The net accelerating force acting on the system is 35,000 N. Therefore, the correct answer is option 'c'.
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A 8000 kg engine pulls a train of 5 wagons, each of 2000 kg along a horizontal track. If the engine exerts aforce of 40,000 N and track offers a friction of 5000 N, then net accelerating force acting on the system is:a)45,000 Nb)40,000 Nc)35,000 Nd)none of the aboveCorrect answer is option 'C'. Can you explain this answer?
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A 8000 kg engine pulls a train of 5 wagons, each of 2000 kg along a horizontal track. If the engine exerts aforce of 40,000 N and track offers a friction of 5000 N, then net accelerating force acting on the system is:a)45,000 Nb)40,000 Nc)35,000 Nd)none of the aboveCorrect answer is option 'C'. Can you explain this answer? for Class 9 2024 is part of Class 9 preparation. The Question and answers have been prepared according to the Class 9 exam syllabus. Information about A 8000 kg engine pulls a train of 5 wagons, each of 2000 kg along a horizontal track. If the engine exerts aforce of 40,000 N and track offers a friction of 5000 N, then net accelerating force acting on the system is:a)45,000 Nb)40,000 Nc)35,000 Nd)none of the aboveCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for Class 9 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A 8000 kg engine pulls a train of 5 wagons, each of 2000 kg along a horizontal track. If the engine exerts aforce of 40,000 N and track offers a friction of 5000 N, then net accelerating force acting on the system is:a)45,000 Nb)40,000 Nc)35,000 Nd)none of the aboveCorrect answer is option 'C'. Can you explain this answer?.
A 8000 kg engine pulls a train of 5 wagons, each of 2000 kg along a horizontal track. If the engine exerts aforce of 40,000 N and track offers a friction of 5000 N, then net accelerating force acting on the system is:a)45,000 Nb)40,000 Nc)35,000 Nd)none of the aboveCorrect answer is option 'C'. Can you explain this answer? for Class 9 2024 is part of Class 9 preparation. The Question and answers have been prepared according to the Class 9 exam syllabus. Information about A 8000 kg engine pulls a train of 5 wagons, each of 2000 kg along a horizontal track. If the engine exerts aforce of 40,000 N and track offers a friction of 5000 N, then net accelerating force acting on the system is:a)45,000 Nb)40,000 Nc)35,000 Nd)none of the aboveCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for Class 9 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A 8000 kg engine pulls a train of 5 wagons, each of 2000 kg along a horizontal track. If the engine exerts aforce of 40,000 N and track offers a friction of 5000 N, then net accelerating force acting on the system is:a)45,000 Nb)40,000 Nc)35,000 Nd)none of the aboveCorrect answer is option 'C'. Can you explain this answer?.
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