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Let X be the set consisting of the first 2018 terms of the arithmetic progression 1, 6, 11, ….. , and Y be the set consisting of the first 2018 terms of arithmetic progression 9, 16, 23, ….. . Then, the number of
elements in the set X ∪ Y is _____ .
    Correct answer is '3748'. Can you explain this answer?
    Verified Answer
    Let X be the set consisting of the first 2018 terms of the arithmetic ...
    n(X ∪Y) = n(X) + n(Y) – n(X ∪Y)
    1, 6, 11, …. 2018 term
    Tn = 1 + (n – 1)5 = 5n – 4
    UK = 9 + (K – 1)7 = 7K + 2
    for common terms
    5n – 4 = 7K + 2
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    Most Upvoted Answer
    Let X be the set consisting of the first 2018 terms of the arithmetic ...
    The first term of the arithmetic progression is $a = 1$, and the common difference is $d = 6 - 1 = 5$. Then the $n$th term is $a + (n - 1) d = 1 + 5(n - 1) = 5n - 4$, so
    \[X = \{ 5n - 4 \mid 1 \le n \le 2018 \}.\]The largest element in the set is $5 \cdot 2018 - 4 = 10090$, so
    \[X = \boxed{\{ 1, 6, 11, \dots, 10090 \}}.\]
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    Let X be the set consisting of the first 2018 terms of the arithmetic ...
    Correct answer is '3748'
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    Let X be the set consisting of the first 2018 terms of the arithmetic progression 1, 6, 11, ….. , and Y be the set consisting of the first 2018 terms of arithmetic progression 9, 16, 23, ….. . Then, the number ofelements in the set X ∪ Y is _____ .Correct answer is '3748'. Can you explain this answer?
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    Let X be the set consisting of the first 2018 terms of the arithmetic progression 1, 6, 11, ….. , and Y be the set consisting of the first 2018 terms of arithmetic progression 9, 16, 23, ….. . Then, the number ofelements in the set X ∪ Y is _____ .Correct answer is '3748'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about Let X be the set consisting of the first 2018 terms of the arithmetic progression 1, 6, 11, ….. , and Y be the set consisting of the first 2018 terms of arithmetic progression 9, 16, 23, ….. . Then, the number ofelements in the set X ∪ Y is _____ .Correct answer is '3748'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Let X be the set consisting of the first 2018 terms of the arithmetic progression 1, 6, 11, ….. , and Y be the set consisting of the first 2018 terms of arithmetic progression 9, 16, 23, ….. . Then, the number ofelements in the set X ∪ Y is _____ .Correct answer is '3748'. Can you explain this answer?.
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