Mechanical Engineering Exam > Mechanical Engineering Questions > Common Data QuestionA centrifugal pump has an...
Start Learning for Free
Common Data Question
A centrifugal pump has an efficiency of 80%. The specifications of the pump are:
Discharge = 70 m3/hr, head = 7 m, speed = 1450 rmp and diameter = 2000 mm. If the speed of this pump is increased to 1750 rpm.
A centrifugal pump has an efficiency of 80%. The specifications of the pump are:
Discharge = 70 m3/hr, head = 7 m, speed = 1450 rmp and diameter = 2000 mm. If the speed of this pump is increased to 1750 rpm.
Q. Power input required is given by:
- a)1.066 kW
- b)1.067 kW
- c)2.12 kW
- d)20 kW
Correct answer is option 'A'. Can you explain this answer?
| FREE This question is part of | Download PDF Attempt this Test |
Verified Answer
Common Data QuestionA centrifugal pump has an efficiency of 80%. The s...
Ans. (a)
Most Upvoted Answer
Common Data QuestionA centrifugal pump has an efficiency of 80%. The s...
Given data:
Efficiency of the pump (η) = 80%
Discharge (Q) = 70 m3/hr
Head (H) = 7 m
Speed (N1) = 1450 rpm
Diameter (D) = 2000 mm
Calculating power input at the given speed:
Power input (P1) can be calculated using the formula:
P1 = (Q * H * ρ * g) / (η * 1000)
where ρ is the density of the fluid being pumped and g is the acceleration due to gravity.
Converting the diameter from mm to m:
Diameter (D) = 2000 mm = 2 m
Calculating the power input at the given speed:
Substituting the given values into the formula, we have:
P1 = (70 * 7 * ρ * g) / (80 * 1000)
Calculating the power input at the increased speed:
New speed (N2) = 1750 rpm
To find the new power input (P2), we can use the affinity laws for pumps:
(P2 / P1) = (N2 / N1)^3
P2 = P1 * (N2 / N1)^3
Substituting the values and calculating P2:
P2 = P1 * (1750 / 1450)^3
Calculating the power input required:
The power input required is given by:
Power input required = P2 - P1
Calculating the final answer:
Substituting the values of P1 and P2, we can calculate the power input required:
Power input required = P2 - P1
Hence, the correct answer is option 'A' - 1.066 kW.
Efficiency of the pump (η) = 80%
Discharge (Q) = 70 m3/hr
Head (H) = 7 m
Speed (N1) = 1450 rpm
Diameter (D) = 2000 mm
Calculating power input at the given speed:
Power input (P1) can be calculated using the formula:
P1 = (Q * H * ρ * g) / (η * 1000)
where ρ is the density of the fluid being pumped and g is the acceleration due to gravity.
Converting the diameter from mm to m:
Diameter (D) = 2000 mm = 2 m
Calculating the power input at the given speed:
Substituting the given values into the formula, we have:
P1 = (70 * 7 * ρ * g) / (80 * 1000)
Calculating the power input at the increased speed:
New speed (N2) = 1750 rpm
To find the new power input (P2), we can use the affinity laws for pumps:
(P2 / P1) = (N2 / N1)^3
P2 = P1 * (N2 / N1)^3
Substituting the values and calculating P2:
P2 = P1 * (1750 / 1450)^3
Calculating the power input required:
The power input required is given by:
Power input required = P2 - P1
Calculating the final answer:
Substituting the values of P1 and P2, we can calculate the power input required:
Power input required = P2 - P1
Hence, the correct answer is option 'A' - 1.066 kW.
Attention Mechanical Engineering Students!
To make sure you are not studying endlessly, EduRev has designed Mechanical Engineering study material, with Structured Courses, Videos, & Test Series. Plus get personalized analysis, doubt solving and improvement plans to achieve a great score in Mechanical Engineering.
|
Explore Courses for Mechanical Engineering exam
|
|
Similar Mechanical Engineering Doubts
Top Courses for Mechanical EngineeringView all
Common Data QuestionA centrifugal pump has an efficiency of 80%. The specifications of the pump are:Discharge = 70 m3/hr, head = 7 m, speed = 1450 rmp and diameter = 2000 mm. If the speed of this pump is increased to 1750 rpm.Q.Power input required is given by:a)1.066 kWb)1.067 kWc)2.12 kWd)20 kWCorrect answer is option 'A'. Can you explain this answer?
Question Description
Common Data QuestionA centrifugal pump has an efficiency of 80%. The specifications of the pump are:Discharge = 70 m3/hr, head = 7 m, speed = 1450 rmp and diameter = 2000 mm. If the speed of this pump is increased to 1750 rpm.Q.Power input required is given by:a)1.066 kWb)1.067 kWc)2.12 kWd)20 kWCorrect answer is option 'A'. Can you explain this answer? for Mechanical Engineering 2024 is part of Mechanical Engineering preparation. The Question and answers have been prepared according to the Mechanical Engineering exam syllabus. Information about Common Data QuestionA centrifugal pump has an efficiency of 80%. The specifications of the pump are:Discharge = 70 m3/hr, head = 7 m, speed = 1450 rmp and diameter = 2000 mm. If the speed of this pump is increased to 1750 rpm.Q.Power input required is given by:a)1.066 kWb)1.067 kWc)2.12 kWd)20 kWCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for Mechanical Engineering 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Common Data QuestionA centrifugal pump has an efficiency of 80%. The specifications of the pump are:Discharge = 70 m3/hr, head = 7 m, speed = 1450 rmp and diameter = 2000 mm. If the speed of this pump is increased to 1750 rpm.Q.Power input required is given by:a)1.066 kWb)1.067 kWc)2.12 kWd)20 kWCorrect answer is option 'A'. Can you explain this answer?.
Common Data QuestionA centrifugal pump has an efficiency of 80%. The specifications of the pump are:Discharge = 70 m3/hr, head = 7 m, speed = 1450 rmp and diameter = 2000 mm. If the speed of this pump is increased to 1750 rpm.Q.Power input required is given by:a)1.066 kWb)1.067 kWc)2.12 kWd)20 kWCorrect answer is option 'A'. Can you explain this answer? for Mechanical Engineering 2024 is part of Mechanical Engineering preparation. The Question and answers have been prepared according to the Mechanical Engineering exam syllabus. Information about Common Data QuestionA centrifugal pump has an efficiency of 80%. The specifications of the pump are:Discharge = 70 m3/hr, head = 7 m, speed = 1450 rmp and diameter = 2000 mm. If the speed of this pump is increased to 1750 rpm.Q.Power input required is given by:a)1.066 kWb)1.067 kWc)2.12 kWd)20 kWCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for Mechanical Engineering 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Common Data QuestionA centrifugal pump has an efficiency of 80%. The specifications of the pump are:Discharge = 70 m3/hr, head = 7 m, speed = 1450 rmp and diameter = 2000 mm. If the speed of this pump is increased to 1750 rpm.Q.Power input required is given by:a)1.066 kWb)1.067 kWc)2.12 kWd)20 kWCorrect answer is option 'A'. Can you explain this answer?.
Solutions for Common Data QuestionA centrifugal pump has an efficiency of 80%. The specifications of the pump are:Discharge = 70 m3/hr, head = 7 m, speed = 1450 rmp and diameter = 2000 mm. If the speed of this pump is increased to 1750 rpm.Q.Power input required is given by:a)1.066 kWb)1.067 kWc)2.12 kWd)20 kWCorrect answer is option 'A'. Can you explain this answer? in English & in Hindi are available as part of our courses for Mechanical Engineering.
Download more important topics, notes, lectures and mock test series for Mechanical Engineering Exam by signing up for free.
Here you can find the meaning of Common Data QuestionA centrifugal pump has an efficiency of 80%. The specifications of the pump are:Discharge = 70 m3/hr, head = 7 m, speed = 1450 rmp and diameter = 2000 mm. If the speed of this pump is increased to 1750 rpm.Q.Power input required is given by:a)1.066 kWb)1.067 kWc)2.12 kWd)20 kWCorrect answer is option 'A'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of
Common Data QuestionA centrifugal pump has an efficiency of 80%. The specifications of the pump are:Discharge = 70 m3/hr, head = 7 m, speed = 1450 rmp and diameter = 2000 mm. If the speed of this pump is increased to 1750 rpm.Q.Power input required is given by:a)1.066 kWb)1.067 kWc)2.12 kWd)20 kWCorrect answer is option 'A'. Can you explain this answer?, a detailed solution for Common Data QuestionA centrifugal pump has an efficiency of 80%. The specifications of the pump are:Discharge = 70 m3/hr, head = 7 m, speed = 1450 rmp and diameter = 2000 mm. If the speed of this pump is increased to 1750 rpm.Q.Power input required is given by:a)1.066 kWb)1.067 kWc)2.12 kWd)20 kWCorrect answer is option 'A'. Can you explain this answer? has been provided alongside types of Common Data QuestionA centrifugal pump has an efficiency of 80%. The specifications of the pump are:Discharge = 70 m3/hr, head = 7 m, speed = 1450 rmp and diameter = 2000 mm. If the speed of this pump is increased to 1750 rpm.Q.Power input required is given by:a)1.066 kWb)1.067 kWc)2.12 kWd)20 kWCorrect answer is option 'A'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice Common Data QuestionA centrifugal pump has an efficiency of 80%. The specifications of the pump are:Discharge = 70 m3/hr, head = 7 m, speed = 1450 rmp and diameter = 2000 mm. If the speed of this pump is increased to 1750 rpm.Q.Power input required is given by:a)1.066 kWb)1.067 kWc)2.12 kWd)20 kWCorrect answer is option 'A'. Can you explain this answer? tests, examples and also practice Mechanical Engineering tests.
|
|
Explore Courses for Mechanical Engineering exam
|
|
Suggested Free Tests
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
|
© EduRev
|
Education Revolution
|
Follow Us
|
Signup to see your scores
go up within 7 days!
Access 1000+ FREE Docs, Videos and Tests
Takes less than 10 seconds to signup