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A quarter cylinder of radius R and refractive index 1.5 is placed on a table. A point object P is kept at a distance of mR from it. Find the value of m for which a ray from P will emerge parallel to the table ? Ans - m=4/3 Can someone please give the solution.?
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A quarter cylinder of radius R and refractive index 1.5 is placed on a...
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A quarter cylinder of radius R and refractive index 1.5 is placed on a...
Solution:

Given:
- Radius of quarter cylinder, R
- Refractive index of quarter cylinder, n = 1.5
- Object distance from quarter cylinder, mR

Formula:
The formula used for refraction is:
n1 * sin(θ1) = n2 * sin(θ2)

Approach:
1. Consider the ray of light entering the quarter cylinder from point P.
2. Let the angle of incidence at the point of entry be θ1 and the angle of refraction inside the cylinder be θ2.
3. Since the ray emerges parallel to the table, the angle of refraction inside the cylinder is 90 degrees.
4. Apply Snell's Law at the point of entry to find the value of m.

Calculation:
n * sin(θ1) = n * sin(90)
1.5 * sin(θ1) = 1.5 * 1
sin(θ1) = 1
θ1 = 90 degrees
As sin(90) = 1, the ray will emerge parallel to the table when the angle of incidence at the point of entry is 90 degrees. This happens when the object distance is equal to the radius of the quarter cylinder, i.e., m = 1.
Therefore, the value of m for which a ray from point P will emerge parallel to the table is m = 1.
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A quarter cylinder of radius R and refractive index 1.5 is placed on a table. A point object P is kept at a distance of mR from it. Find the value of m for which a ray from P will emerge parallel to the table ? Ans - m=4/3 Can someone please give the solution.?
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A quarter cylinder of radius R and refractive index 1.5 is placed on a table. A point object P is kept at a distance of mR from it. Find the value of m for which a ray from P will emerge parallel to the table ? Ans - m=4/3 Can someone please give the solution.? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about A quarter cylinder of radius R and refractive index 1.5 is placed on a table. A point object P is kept at a distance of mR from it. Find the value of m for which a ray from P will emerge parallel to the table ? Ans - m=4/3 Can someone please give the solution.? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A quarter cylinder of radius R and refractive index 1.5 is placed on a table. A point object P is kept at a distance of mR from it. Find the value of m for which a ray from P will emerge parallel to the table ? Ans - m=4/3 Can someone please give the solution.?.
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