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An organic compound A (C7H16O) shows both enantiomerism and diastereomerism. Treatment of a pure enantiomer of A with Na2CrO4 /Dil. H2SO4 gives B (C7H14O) - Also A on dehydration with concentrated H2SO4 gives a single alkene C (C7H14). Ozonolysis of C followed by work-up with Zn-H2O gives D (C5H10O) as one of the product which gives racemic mixture on reduction with NaBH4.
Q.
The correct statement regarding the compound D is
- a)With CH3MgBr followed by acid hydrolysis gives racemic mixture
- b)With CH3CH2CH2MgBr followed by acid hydrolysis gives racemic mixture
- c)With CH3CH2MgBr followed by acid hydrolysis gives racemic mixture
- d)Both (b) and (c) are correct
Correct answer is option 'C'. Can you explain this answer?
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An organic compound A (C7H16O) shows both enantiomerism and diastereom...
Since, A is completely saturated, it must contain more than one chiral carbon atoms in order to show both enantiomerism and diastereomerism. Also, C on ozonolysis gives D (C5H10O) as one product, other product must be CH3SHO. Hence, C must be 
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An organic compound A (C7H16O) shows both enantiomerism and diastereom...
Enantiomerism and Diastereomerism of Compound A
- Enantiomerism refers to the existence of mirror-image isomers, also known as enantiomers. Enantiomers have the same molecular formula but differ in their spatial arrangement.
- Diastereomerism refers to the existence of stereoisomers that are not mirror images of each other. Diastereomers have different physical and chemical properties.
Reaction of Compound A with Na2CrO4/Dil. H2SO4
- Treatment of a pure enantiomer of compound A with Na2CrO4/Dil. H2SO4 results in the formation of compound B (C7H14O).
- The reaction involves oxidation of the alcohol group in compound A to a carbonyl group in compound B.
Dehydration of Compound A with Concentrated H2SO4
- Dehydration of compound A with concentrated H2SO4 leads to the formation of a single alkene, compound C (C7H14).
- The reaction involves the removal of a water molecule from compound A, resulting in the formation of a double bond.
Ozonolysis of Compound C followed by Work-up with Zn-H2O
- Ozonolysis of compound C followed by work-up with Zn-H2O gives compound D (C5H10O) as one of the products.
- The reaction involves the cleavage of the double bond in compound C by ozone, resulting in the formation of two carbonyl groups.
- The presence of Zn-H2O reduces one of the carbonyl groups, resulting in the formation of compound D.
Reduction of Compound D with NaBH4
- Reduction of compound D with NaBH4 gives a racemic mixture.
- NaBH4 is a mild reducing agent that can selectively reduce one of the carbonyl groups in compound D, resulting in the formation of a chiral center.
- As a result, a racemic mixture is formed, containing both the R and S enantiomers.
Reaction of Compound D with CH3CH2MgBr and Acid Hydrolysis
- Treatment of compound D with CH3CH2MgBr followed by acid hydrolysis gives a racemic mixture.
- CH3CH2MgBr is a Grignard reagent that can react with the carbonyl group in compound D, resulting in the formation of an alcohol.
- Acid hydrolysis of the intermediate alcohol results in the formation of a racemic mixture, as both the R and S enantiomers are formed.
Therefore, the correct statement regarding compound D is option C: With CH3CH2MgBr followed by acid hydrolysis, it gives a racemic mixture.
- Enantiomerism refers to the existence of mirror-image isomers, also known as enantiomers. Enantiomers have the same molecular formula but differ in their spatial arrangement.
- Diastereomerism refers to the existence of stereoisomers that are not mirror images of each other. Diastereomers have different physical and chemical properties.
Reaction of Compound A with Na2CrO4/Dil. H2SO4
- Treatment of a pure enantiomer of compound A with Na2CrO4/Dil. H2SO4 results in the formation of compound B (C7H14O).
- The reaction involves oxidation of the alcohol group in compound A to a carbonyl group in compound B.
Dehydration of Compound A with Concentrated H2SO4
- Dehydration of compound A with concentrated H2SO4 leads to the formation of a single alkene, compound C (C7H14).
- The reaction involves the removal of a water molecule from compound A, resulting in the formation of a double bond.
Ozonolysis of Compound C followed by Work-up with Zn-H2O
- Ozonolysis of compound C followed by work-up with Zn-H2O gives compound D (C5H10O) as one of the products.
- The reaction involves the cleavage of the double bond in compound C by ozone, resulting in the formation of two carbonyl groups.
- The presence of Zn-H2O reduces one of the carbonyl groups, resulting in the formation of compound D.
Reduction of Compound D with NaBH4
- Reduction of compound D with NaBH4 gives a racemic mixture.
- NaBH4 is a mild reducing agent that can selectively reduce one of the carbonyl groups in compound D, resulting in the formation of a chiral center.
- As a result, a racemic mixture is formed, containing both the R and S enantiomers.
Reaction of Compound D with CH3CH2MgBr and Acid Hydrolysis
- Treatment of compound D with CH3CH2MgBr followed by acid hydrolysis gives a racemic mixture.
- CH3CH2MgBr is a Grignard reagent that can react with the carbonyl group in compound D, resulting in the formation of an alcohol.
- Acid hydrolysis of the intermediate alcohol results in the formation of a racemic mixture, as both the R and S enantiomers are formed.
Therefore, the correct statement regarding compound D is option C: With CH3CH2MgBr followed by acid hydrolysis, it gives a racemic mixture.
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An organic compound A (C7H16O) shows both enantiomerism and diastereomerism. Treatment of a pure enantiomer of A with Na2CrO4 /Dil. H2SO4 gives B(C7H14O) - Also A on dehydration with concentrated H2SO4 gives a single alkene C (C7H14). Ozonolysis of C followed by work-up with Zn-H2Ogives D (C5H10O) as one of the product which gives racemic mixture on reduction with NaBH4.Q.The correct statement regarding the compound D isa)With CH3MgBr followed by acid hydrolysis gives racemic mixtureb)With CH3CH2CH2MgBr followed by acid hydrolysis gives racemic mixturec)With CH3CH2MgBr followed by acid hydrolysis gives racemic mixtured)Both (b) and (c) are correctCorrect answer is option 'C'. Can you explain this answer?
Question Description
An organic compound A (C7H16O) shows both enantiomerism and diastereomerism. Treatment of a pure enantiomer of A with Na2CrO4 /Dil. H2SO4 gives B(C7H14O) - Also A on dehydration with concentrated H2SO4 gives a single alkene C (C7H14). Ozonolysis of C followed by work-up with Zn-H2Ogives D (C5H10O) as one of the product which gives racemic mixture on reduction with NaBH4.Q.The correct statement regarding the compound D isa)With CH3MgBr followed by acid hydrolysis gives racemic mixtureb)With CH3CH2CH2MgBr followed by acid hydrolysis gives racemic mixturec)With CH3CH2MgBr followed by acid hydrolysis gives racemic mixtured)Both (b) and (c) are correctCorrect answer is option 'C'. Can you explain this answer? for Class 12 2024 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about An organic compound A (C7H16O) shows both enantiomerism and diastereomerism. Treatment of a pure enantiomer of A with Na2CrO4 /Dil. H2SO4 gives B(C7H14O) - Also A on dehydration with concentrated H2SO4 gives a single alkene C (C7H14). Ozonolysis of C followed by work-up with Zn-H2Ogives D (C5H10O) as one of the product which gives racemic mixture on reduction with NaBH4.Q.The correct statement regarding the compound D isa)With CH3MgBr followed by acid hydrolysis gives racemic mixtureb)With CH3CH2CH2MgBr followed by acid hydrolysis gives racemic mixturec)With CH3CH2MgBr followed by acid hydrolysis gives racemic mixtured)Both (b) and (c) are correctCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for Class 12 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for An organic compound A (C7H16O) shows both enantiomerism and diastereomerism. Treatment of a pure enantiomer of A with Na2CrO4 /Dil. H2SO4 gives B(C7H14O) - Also A on dehydration with concentrated H2SO4 gives a single alkene C (C7H14). Ozonolysis of C followed by work-up with Zn-H2Ogives D (C5H10O) as one of the product which gives racemic mixture on reduction with NaBH4.Q.The correct statement regarding the compound D isa)With CH3MgBr followed by acid hydrolysis gives racemic mixtureb)With CH3CH2CH2MgBr followed by acid hydrolysis gives racemic mixturec)With CH3CH2MgBr followed by acid hydrolysis gives racemic mixtured)Both (b) and (c) are correctCorrect answer is option 'C'. Can you explain this answer?.
An organic compound A (C7H16O) shows both enantiomerism and diastereomerism. Treatment of a pure enantiomer of A with Na2CrO4 /Dil. H2SO4 gives B(C7H14O) - Also A on dehydration with concentrated H2SO4 gives a single alkene C (C7H14). Ozonolysis of C followed by work-up with Zn-H2Ogives D (C5H10O) as one of the product which gives racemic mixture on reduction with NaBH4.Q.The correct statement regarding the compound D isa)With CH3MgBr followed by acid hydrolysis gives racemic mixtureb)With CH3CH2CH2MgBr followed by acid hydrolysis gives racemic mixturec)With CH3CH2MgBr followed by acid hydrolysis gives racemic mixtured)Both (b) and (c) are correctCorrect answer is option 'C'. Can you explain this answer? for Class 12 2024 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about An organic compound A (C7H16O) shows both enantiomerism and diastereomerism. Treatment of a pure enantiomer of A with Na2CrO4 /Dil. H2SO4 gives B(C7H14O) - Also A on dehydration with concentrated H2SO4 gives a single alkene C (C7H14). Ozonolysis of C followed by work-up with Zn-H2Ogives D (C5H10O) as one of the product which gives racemic mixture on reduction with NaBH4.Q.The correct statement regarding the compound D isa)With CH3MgBr followed by acid hydrolysis gives racemic mixtureb)With CH3CH2CH2MgBr followed by acid hydrolysis gives racemic mixturec)With CH3CH2MgBr followed by acid hydrolysis gives racemic mixtured)Both (b) and (c) are correctCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for Class 12 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for An organic compound A (C7H16O) shows both enantiomerism and diastereomerism. Treatment of a pure enantiomer of A with Na2CrO4 /Dil. H2SO4 gives B(C7H14O) - Also A on dehydration with concentrated H2SO4 gives a single alkene C (C7H14). Ozonolysis of C followed by work-up with Zn-H2Ogives D (C5H10O) as one of the product which gives racemic mixture on reduction with NaBH4.Q.The correct statement regarding the compound D isa)With CH3MgBr followed by acid hydrolysis gives racemic mixtureb)With CH3CH2CH2MgBr followed by acid hydrolysis gives racemic mixturec)With CH3CH2MgBr followed by acid hydrolysis gives racemic mixtured)Both (b) and (c) are correctCorrect answer is option 'C'. Can you explain this answer?.
Solutions for An organic compound A (C7H16O) shows both enantiomerism and diastereomerism. Treatment of a pure enantiomer of A with Na2CrO4 /Dil. H2SO4 gives B(C7H14O) - Also A on dehydration with concentrated H2SO4 gives a single alkene C (C7H14). Ozonolysis of C followed by work-up with Zn-H2Ogives D (C5H10O) as one of the product which gives racemic mixture on reduction with NaBH4.Q.The correct statement regarding the compound D isa)With CH3MgBr followed by acid hydrolysis gives racemic mixtureb)With CH3CH2CH2MgBr followed by acid hydrolysis gives racemic mixturec)With CH3CH2MgBr followed by acid hydrolysis gives racemic mixtured)Both (b) and (c) are correctCorrect answer is option 'C'. Can you explain this answer? in English & in Hindi are available as part of our courses for Class 12.
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Here you can find the meaning of An organic compound A (C7H16O) shows both enantiomerism and diastereomerism. Treatment of a pure enantiomer of A with Na2CrO4 /Dil. H2SO4 gives B(C7H14O) - Also A on dehydration with concentrated H2SO4 gives a single alkene C (C7H14). Ozonolysis of C followed by work-up with Zn-H2Ogives D (C5H10O) as one of the product which gives racemic mixture on reduction with NaBH4.Q.The correct statement regarding the compound D isa)With CH3MgBr followed by acid hydrolysis gives racemic mixtureb)With CH3CH2CH2MgBr followed by acid hydrolysis gives racemic mixturec)With CH3CH2MgBr followed by acid hydrolysis gives racemic mixtured)Both (b) and (c) are correctCorrect answer is option 'C'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of
An organic compound A (C7H16O) shows both enantiomerism and diastereomerism. Treatment of a pure enantiomer of A with Na2CrO4 /Dil. H2SO4 gives B(C7H14O) - Also A on dehydration with concentrated H2SO4 gives a single alkene C (C7H14). Ozonolysis of C followed by work-up with Zn-H2Ogives D (C5H10O) as one of the product which gives racemic mixture on reduction with NaBH4.Q.The correct statement regarding the compound D isa)With CH3MgBr followed by acid hydrolysis gives racemic mixtureb)With CH3CH2CH2MgBr followed by acid hydrolysis gives racemic mixturec)With CH3CH2MgBr followed by acid hydrolysis gives racemic mixtured)Both (b) and (c) are correctCorrect answer is option 'C'. Can you explain this answer?, a detailed solution for An organic compound A (C7H16O) shows both enantiomerism and diastereomerism. Treatment of a pure enantiomer of A with Na2CrO4 /Dil. H2SO4 gives B(C7H14O) - Also A on dehydration with concentrated H2SO4 gives a single alkene C (C7H14). Ozonolysis of C followed by work-up with Zn-H2Ogives D (C5H10O) as one of the product which gives racemic mixture on reduction with NaBH4.Q.The correct statement regarding the compound D isa)With CH3MgBr followed by acid hydrolysis gives racemic mixtureb)With CH3CH2CH2MgBr followed by acid hydrolysis gives racemic mixturec)With CH3CH2MgBr followed by acid hydrolysis gives racemic mixtured)Both (b) and (c) are correctCorrect answer is option 'C'. Can you explain this answer? has been provided alongside types of An organic compound A (C7H16O) shows both enantiomerism and diastereomerism. Treatment of a pure enantiomer of A with Na2CrO4 /Dil. H2SO4 gives B(C7H14O) - Also A on dehydration with concentrated H2SO4 gives a single alkene C (C7H14). Ozonolysis of C followed by work-up with Zn-H2Ogives D (C5H10O) as one of the product which gives racemic mixture on reduction with NaBH4.Q.The correct statement regarding the compound D isa)With CH3MgBr followed by acid hydrolysis gives racemic mixtureb)With CH3CH2CH2MgBr followed by acid hydrolysis gives racemic mixturec)With CH3CH2MgBr followed by acid hydrolysis gives racemic mixtured)Both (b) and (c) are correctCorrect answer is option 'C'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice An organic compound A (C7H16O) shows both enantiomerism and diastereomerism. Treatment of a pure enantiomer of A with Na2CrO4 /Dil. H2SO4 gives B(C7H14O) - Also A on dehydration with concentrated H2SO4 gives a single alkene C (C7H14). Ozonolysis of C followed by work-up with Zn-H2Ogives D (C5H10O) as one of the product which gives racemic mixture on reduction with NaBH4.Q.The correct statement regarding the compound D isa)With CH3MgBr followed by acid hydrolysis gives racemic mixtureb)With CH3CH2CH2MgBr followed by acid hydrolysis gives racemic mixturec)With CH3CH2MgBr followed by acid hydrolysis gives racemic mixtured)Both (b) and (c) are correctCorrect answer is option 'C'. Can you explain this answer? tests, examples and also practice Class 12 tests.
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