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The ammonia prepared by treating ammonium sulphate with calcium hydroxide is completely used by
NiCl2.6H2O to form a stable coordination compound. Assume that both the reactions are 100% complete. If 1584 g of ammonium sulphate and 952 g of NiCl2.6H2O are used in the preparation, the combined weight (in grams) of gypsum and the nickel-ammonia coordination compound thus produced is ____.
(Atomic weights in g mol–1 : H = 1, N = 14, O = 16, S = 32, Cl = 35.5, Ca = 40, Ni = 59)
NiCl2.6H2O to form a stable coordination compound. Assume that both the reactions are 100% complete. If 1584 g of ammonium sulphate and 952 g of NiCl2.6H2O are used in the preparation, the combined weight (in grams) of gypsum and the nickel-ammonia coordination compound thus produced is ____.
(Atomic weights in g mol–1 : H = 1, N = 14, O = 16, S = 32, Cl = 35.5, Ca = 40, Ni = 59)
Correct answer is '2992'. Can you explain this answer?
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The ammonia prepared by treating ammonium sulphate with calcium hydrox...
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To determine the combined weight of gypsum and the nickel-ammonia coordination compound produced, we first need to calculate the moles of ammonium sulfate and NiCl2.6H2O used.
1. Calculate the moles of ammonium sulfate:
Molar mass of ammonium sulfate (NH4)2SO4 = (2*14.01) + (4*1.01) + 32.07 + (4*16.00)
= 132.14 g/mol
Moles of ammonium sulfate = mass / molar mass
= 1584 g / 132.14 g/mol
= 12 mol
2. Calculate the moles of NiCl2.6H2O:
Molar mass of NiCl2.6H2O = (58.69 + 2*35.45) + 6*(2*1.01 + 16.00)
= 237.69 g/mol
Moles of NiCl2.6H2O = mass / molar mass
= 952 g / 237.69 g/mol
= 4 mol
Now, based on the balanced chemical equation, we can determine the stoichiometry of the reaction between ammonium sulfate and calcium hydroxide to form gypsum (calcium sulfate) and ammonia:
(NH4)2SO4 + Ca(OH)2 → CaSO4 + 2NH3 + 2H2O
From the equation, we can see that 1 mole of ammonium sulfate reacts with 1 mole of calcium hydroxide to form 1 mole of calcium sulfate and 2 moles of ammonia. Therefore, the moles of ammonia produced will be equal to the moles of ammonium sulfate used.
Moles of ammonia = 12 mol
Now, let's consider the reaction between NiCl2.6H2O and ammonia:
NiCl2.6H2O + 6NH3 → [Ni(NH3)6]Cl2 + 6H2O
From the equation, we can see that 1 mole of NiCl2.6H2O reacts with 6 moles of ammonia to form 1 mole of [Ni(NH3)6]Cl2. Therefore, moles of [Ni(NH3)6]Cl2 produced will be equal to the moles of ammonia used.
Moles of [Ni(NH3)6]Cl2 = 12 mol
Now, we need to calculate the molar mass of gypsum (calcium sulfate) and [Ni(NH3)6]Cl2 to determine their combined weight.
3. Calculate the molar mass of gypsum (CaSO4):
Molar mass of CaSO4 = 40.08 + 32.07 + (4*16.00)
= 136.14 g/mol
4. Calculate the molar mass of [Ni(NH3)6]Cl2:
Molar mass of Ni(NH3)6Cl2 = 58.69 + 6*(14.01 + 3*1.01) + 2*(35.45)
= 237.69 g/mol
Finally, we can calculate the combined weight of gypsum and the nickel-ammonia coordination compound:
Combined weight = (moles of gypsum * molar mass of gypsum) + (moles of [Ni
1. Calculate the moles of ammonium sulfate:
Molar mass of ammonium sulfate (NH4)2SO4 = (2*14.01) + (4*1.01) + 32.07 + (4*16.00)
= 132.14 g/mol
Moles of ammonium sulfate = mass / molar mass
= 1584 g / 132.14 g/mol
= 12 mol
2. Calculate the moles of NiCl2.6H2O:
Molar mass of NiCl2.6H2O = (58.69 + 2*35.45) + 6*(2*1.01 + 16.00)
= 237.69 g/mol
Moles of NiCl2.6H2O = mass / molar mass
= 952 g / 237.69 g/mol
= 4 mol
Now, based on the balanced chemical equation, we can determine the stoichiometry of the reaction between ammonium sulfate and calcium hydroxide to form gypsum (calcium sulfate) and ammonia:
(NH4)2SO4 + Ca(OH)2 → CaSO4 + 2NH3 + 2H2O
From the equation, we can see that 1 mole of ammonium sulfate reacts with 1 mole of calcium hydroxide to form 1 mole of calcium sulfate and 2 moles of ammonia. Therefore, the moles of ammonia produced will be equal to the moles of ammonium sulfate used.
Moles of ammonia = 12 mol
Now, let's consider the reaction between NiCl2.6H2O and ammonia:
NiCl2.6H2O + 6NH3 → [Ni(NH3)6]Cl2 + 6H2O
From the equation, we can see that 1 mole of NiCl2.6H2O reacts with 6 moles of ammonia to form 1 mole of [Ni(NH3)6]Cl2. Therefore, moles of [Ni(NH3)6]Cl2 produced will be equal to the moles of ammonia used.
Moles of [Ni(NH3)6]Cl2 = 12 mol
Now, we need to calculate the molar mass of gypsum (calcium sulfate) and [Ni(NH3)6]Cl2 to determine their combined weight.
3. Calculate the molar mass of gypsum (CaSO4):
Molar mass of CaSO4 = 40.08 + 32.07 + (4*16.00)
= 136.14 g/mol
4. Calculate the molar mass of [Ni(NH3)6]Cl2:
Molar mass of Ni(NH3)6Cl2 = 58.69 + 6*(14.01 + 3*1.01) + 2*(35.45)
= 237.69 g/mol
Finally, we can calculate the combined weight of gypsum and the nickel-ammonia coordination compound:
Combined weight = (moles of gypsum * molar mass of gypsum) + (moles of [Ni
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The ammonia prepared by treating ammonium sulphate with calcium hydroxide is completely used byNiCl2.6H2O to form a stable coordination compound. Assume that both the reactions are 100% complete. If 1584 g of ammonium sulphate and 952 g of NiCl2.6H2O are used in the preparation, the combined weight (in grams) of gypsum and the nickel-ammonia coordination compound thus produced is ____.(Atomic weights in g mol–1 : H = 1, N = 14, O = 16, S = 32, Cl = 35.5, Ca = 40, Ni = 59)Correct answer is '2992'. Can you explain this answer?
Question Description
The ammonia prepared by treating ammonium sulphate with calcium hydroxide is completely used byNiCl2.6H2O to form a stable coordination compound. Assume that both the reactions are 100% complete. If 1584 g of ammonium sulphate and 952 g of NiCl2.6H2O are used in the preparation, the combined weight (in grams) of gypsum and the nickel-ammonia coordination compound thus produced is ____.(Atomic weights in g mol–1 : H = 1, N = 14, O = 16, S = 32, Cl = 35.5, Ca = 40, Ni = 59)Correct answer is '2992'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about The ammonia prepared by treating ammonium sulphate with calcium hydroxide is completely used byNiCl2.6H2O to form a stable coordination compound. Assume that both the reactions are 100% complete. If 1584 g of ammonium sulphate and 952 g of NiCl2.6H2O are used in the preparation, the combined weight (in grams) of gypsum and the nickel-ammonia coordination compound thus produced is ____.(Atomic weights in g mol–1 : H = 1, N = 14, O = 16, S = 32, Cl = 35.5, Ca = 40, Ni = 59)Correct answer is '2992'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The ammonia prepared by treating ammonium sulphate with calcium hydroxide is completely used byNiCl2.6H2O to form a stable coordination compound. Assume that both the reactions are 100% complete. If 1584 g of ammonium sulphate and 952 g of NiCl2.6H2O are used in the preparation, the combined weight (in grams) of gypsum and the nickel-ammonia coordination compound thus produced is ____.(Atomic weights in g mol–1 : H = 1, N = 14, O = 16, S = 32, Cl = 35.5, Ca = 40, Ni = 59)Correct answer is '2992'. Can you explain this answer?.
The ammonia prepared by treating ammonium sulphate with calcium hydroxide is completely used byNiCl2.6H2O to form a stable coordination compound. Assume that both the reactions are 100% complete. If 1584 g of ammonium sulphate and 952 g of NiCl2.6H2O are used in the preparation, the combined weight (in grams) of gypsum and the nickel-ammonia coordination compound thus produced is ____.(Atomic weights in g mol–1 : H = 1, N = 14, O = 16, S = 32, Cl = 35.5, Ca = 40, Ni = 59)Correct answer is '2992'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about The ammonia prepared by treating ammonium sulphate with calcium hydroxide is completely used byNiCl2.6H2O to form a stable coordination compound. Assume that both the reactions are 100% complete. If 1584 g of ammonium sulphate and 952 g of NiCl2.6H2O are used in the preparation, the combined weight (in grams) of gypsum and the nickel-ammonia coordination compound thus produced is ____.(Atomic weights in g mol–1 : H = 1, N = 14, O = 16, S = 32, Cl = 35.5, Ca = 40, Ni = 59)Correct answer is '2992'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The ammonia prepared by treating ammonium sulphate with calcium hydroxide is completely used byNiCl2.6H2O to form a stable coordination compound. Assume that both the reactions are 100% complete. If 1584 g of ammonium sulphate and 952 g of NiCl2.6H2O are used in the preparation, the combined weight (in grams) of gypsum and the nickel-ammonia coordination compound thus produced is ____.(Atomic weights in g mol–1 : H = 1, N = 14, O = 16, S = 32, Cl = 35.5, Ca = 40, Ni = 59)Correct answer is '2992'. Can you explain this answer?.
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The ammonia prepared by treating ammonium sulphate with calcium hydroxide is completely used byNiCl2.6H2O to form a stable coordination compound. Assume that both the reactions are 100% complete. If 1584 g of ammonium sulphate and 952 g of NiCl2.6H2O are used in the preparation, the combined weight (in grams) of gypsum and the nickel-ammonia coordination compound thus produced is ____.(Atomic weights in g mol–1 : H = 1, N = 14, O = 16, S = 32, Cl = 35.5, Ca = 40, Ni = 59)Correct answer is '2992'. Can you explain this answer?, a detailed solution for The ammonia prepared by treating ammonium sulphate with calcium hydroxide is completely used byNiCl2.6H2O to form a stable coordination compound. Assume that both the reactions are 100% complete. If 1584 g of ammonium sulphate and 952 g of NiCl2.6H2O are used in the preparation, the combined weight (in grams) of gypsum and the nickel-ammonia coordination compound thus produced is ____.(Atomic weights in g mol–1 : H = 1, N = 14, O = 16, S = 32, Cl = 35.5, Ca = 40, Ni = 59)Correct answer is '2992'. Can you explain this answer? has been provided alongside types of The ammonia prepared by treating ammonium sulphate with calcium hydroxide is completely used byNiCl2.6H2O to form a stable coordination compound. Assume that both the reactions are 100% complete. If 1584 g of ammonium sulphate and 952 g of NiCl2.6H2O are used in the preparation, the combined weight (in grams) of gypsum and the nickel-ammonia coordination compound thus produced is ____.(Atomic weights in g mol–1 : H = 1, N = 14, O = 16, S = 32, Cl = 35.5, Ca = 40, Ni = 59)Correct answer is '2992'. Can you explain this answer? theory, EduRev gives you an
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