A man starts running from point P at 11:00 a.m. with a speed of 10 km/...
To solve this problem, let's break it down into smaller steps:
1. Determine the distance covered by the first man during each running cycle.
2. Calculate the time it takes for the second man to cover the same distance.
3. Find the total time taken for the first man to be caught.
4. Convert the total time into hours and minutes.
5. Determine the time at which the first man is caught.
Step 1: Distance covered by the first man during each running cycle
The first man runs for 2 hours at a speed of 10 km/hr. Therefore, the distance covered during each running cycle is:
Distance = Speed x Time
Distance = 10 km/hr x 2 hr
Distance = 20 km
Step 2: Time taken for the second man to cover the same distance
The second man runs at a speed of 15 km/hr towards the first man. Therefore, the time taken for the second man to cover 20 km is:
Time = Distance / Speed
Time = 20 km / 15 km/hr
Time = 4/3 hr
Time = 1 hour and 20 minutes
Step 3: Total time taken for the first man to be caught
The first man runs for 2 hours and then takes a 1-hour rest. This pattern repeats until he is caught. Therefore, the total time taken for the first man to be caught is:
Total Time = 2 hours (running time) + 1 hour (rest time)
Total Time = 3 hours
Step 4: Convert the total time into hours and minutes
Since the first man starts running at 11:00 a.m., adding 3 hours will give us the time at which he is caught:
11:00 a.m. + 3 hours = 2:00 p.m.
Step 5: Determine the time at which the first man is caught
The second man starts running at 2:00 p.m. and takes 1 hour and 20 minutes to cover the distance of 20 km. Adding this time to 2:00 p.m. will give us the time at which the first man is caught:
2:00 p.m. + 1 hour and 20 minutes = 3:20 p.m.
Therefore, the first man will be caught at 3:20 p.m., which corresponds to option B, 4:40 p.m.