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In IO2F2-, let be x the total number of bond pairs in the molecule, y be the total number of lone pairs in the molecule and z be the total number of 90 degree angles in IO2F2-, then x y z is?
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In IO2F2-, let be x the total number of bond pairs in the molecule, y ...
Ans.

Method to Solve :

this question is based on valence shell electron pair repulsion theory,

bond pair = 4

lone pair = 1/2 (Valence electrons - 8 x bond pair )

= 1/2 (1 x 7 + 2 x 6 + 7 x 2 + 1 - 8 x 4)

= 1/2 (7 + 12 + 14 + 1 - 32)

= 1/2 (34 - 32)

= 1

hence, lone pair = 1

so, hybridisation of given molecule is sp�d and hence, shape of molecule is trigonal pyramidal but in the presence of one lone pair, one bond is removed from trigonal pyramidal then shape will be like seesaw.

so, total no of 90� angle = 3

then, x + y + z = 4 + 1 + 3 = 8
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In IO2F2-, let be x the total number of bond pairs in the molecule, y ...
The molecule IO2F2- consists of iodine (I) as the central atom bonded to two oxygen atoms (O) and two fluorine atoms (F). To determine the total number of bond pairs (x), lone pairs (y), and 90-degree angles (z) in IO2F2-, let's analyze its Lewis structure and molecular geometry.

Lewis Structure:
1. Start by placing the central atom (I) in the center and connect it to the surrounding atoms (O and F) using single bonds.
2. The oxygen atoms (O) are more electronegative than iodine (I), so they will have three lone pairs each.
3. The fluorine atoms (F) will each have three lone pairs as well.

Molecular Geometry:
1. The molecule has a trigonal bipyramidal geometry.
2. The two oxygen atoms (O) and two fluorine atoms (F) will occupy the equatorial positions, while the iodine atom (I) will be in the axial position.
3. The axial position results in a linear arrangement, while the equatorial positions form a trigonal planar arrangement.

Now, let's determine the values of x, y, and z based on the Lewis structure and molecular geometry.

Number of Bond Pairs (x):
- In IO2F2-, there are two I-O bonds and two I-F bonds.
- Therefore, the total number of bond pairs (x) is 4.

Number of Lone Pairs (y):
- Each oxygen atom (O) has three lone pairs, and there are two oxygen atoms in the molecule. Therefore, the total number of lone pairs from oxygen atoms is 6.
- Each fluorine atom (F) also has three lone pairs, and there are two fluorine atoms in the molecule. Hence, the total number of lone pairs from fluorine atoms is 6.
- Therefore, the total number of lone pairs (y) is 12.

Number of 90-Degree Angles (z):
- In the trigonal planar arrangement of the equatorial positions, there are three 90-degree angles.
- Since there are two equatorial positions, the total number of 90-degree angles (z) is 6.

Summary:
Based on the analysis of IO2F2-, we have determined the values of x, y, and z as follows:
- x (total number of bond pairs) = 4
- y (total number of lone pairs) = 12
- z (total number of 90-degree angles) = 6

Therefore, x y z in IO2F2- is 4 12 6.
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In IO2F2-, let be x the total number of bond pairs in the molecule, y be the total number of lone pairs in the molecule and z be the total number of 90 degree angles in IO2F2-, then x y z is?
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