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The negative sign in the formula of amplification factor indicates_________
- a)that IE flows into transistor while IC flows out it
- b)that IC flows into transistor while IE flows out it
- c)that IB flows into transistor while IC flows out it
- d)that IC flows into transistor while IB flows out it
Correct answer is option 'A'. Can you explain this answer?
Verified Answer
The negative sign in the formula of amplification factor indicates____...
When no signal is applied, the ratio of collector current to emitter current is called dc alpha, αdc of a transistor. αdc=-IC/IE. It is the measure of the quality of a transistor. Higher is the value of α, better is the transistor in the sense that collector current approaches the emitter current.
Most Upvoted Answer
The negative sign in the formula of amplification factor indicates____...
Explanation:
The amplification factor of a transistor is a measure of how much the output current or voltage is amplified with respect to the input current or voltage. It is denoted by the symbol β (beta) for a common-emitter configuration.
The amplification factor, β, is defined as the ratio of the output current, IC, to the input current, IE:
β = IC / IE
In the formula, the negative sign indicates the direction of current flow. Let's understand each option and why option 'A' is the correct answer.
a) that IE flows into the transistor while IC flows out of it:
This option is correct because the negative sign indicates that the direction of current flow is such that the input current, IE, flows into the transistor while the output current, IC, flows out of the transistor. This is consistent with the conventional current flow direction in a transistor.
b) that IC flows into the transistor while IE flows out of it:
This option is incorrect because it suggests that the input current, IE, flows out of the transistor while the output current, IC, flows into the transistor, which is opposite to the conventional current flow direction.
c) that IB flows into the transistor while IC flows out of it:
This option is incorrect because it refers to the base current, IB, instead of the input current, IE. The amplification factor, β, does not involve the base current in its definition.
d) that IC flows into the transistor while IB flows out of it:
This option is incorrect because it suggests that the output current, IC, flows into the transistor while the base current, IB, flows out of the transistor, which is opposite to the conventional current flow direction.
Conclusion:
The negative sign in the formula of the amplification factor indicates that the input current, IE, flows into the transistor while the output current, IC, flows out of the transistor.
The amplification factor of a transistor is a measure of how much the output current or voltage is amplified with respect to the input current or voltage. It is denoted by the symbol β (beta) for a common-emitter configuration.
The amplification factor, β, is defined as the ratio of the output current, IC, to the input current, IE:
β = IC / IE
In the formula, the negative sign indicates the direction of current flow. Let's understand each option and why option 'A' is the correct answer.
a) that IE flows into the transistor while IC flows out of it:
This option is correct because the negative sign indicates that the direction of current flow is such that the input current, IE, flows into the transistor while the output current, IC, flows out of the transistor. This is consistent with the conventional current flow direction in a transistor.
b) that IC flows into the transistor while IE flows out of it:
This option is incorrect because it suggests that the input current, IE, flows out of the transistor while the output current, IC, flows into the transistor, which is opposite to the conventional current flow direction.
c) that IB flows into the transistor while IC flows out of it:
This option is incorrect because it refers to the base current, IB, instead of the input current, IE. The amplification factor, β, does not involve the base current in its definition.
d) that IC flows into the transistor while IB flows out of it:
This option is incorrect because it suggests that the output current, IC, flows into the transistor while the base current, IB, flows out of the transistor, which is opposite to the conventional current flow direction.
Conclusion:
The negative sign in the formula of the amplification factor indicates that the input current, IE, flows into the transistor while the output current, IC, flows out of the transistor.
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