A dealer sells two bikes at Rs 14000 each. On one he gains 20% and on ...
On the first bike, the dealer gains 20%, which means he sells it for 120% of its cost price. Let the cost price of the first bike be x. Then:
120% of x = Rs 14000
1.2x = 14000
x = 11666.67
So, the dealer's profit on the first bike is Rs 14000 - Rs 11666.67 = Rs 2333.33
On the second bike, the dealer loses 20%, which means he sells it for 80% of its cost price. Let the cost price of the second bike be y. Then:
80% of y = Rs 14000
0.8y = 14000
y = 17500
So, the dealer's loss on the second bike is Rs 17500 - Rs 14000 = Rs 3500
Therefore, the dealer's total profit/loss on the two bikes is Rs 2333.33 - Rs 3500 = Rs -1166.67, which is a loss of 1166.67/28000 * 100% = 4.16%.
Now, if the dealer had marked up the prices by 25%, the selling price of each bike would have been Rs 17500. After giving a 10% discount, the selling price of each bike would have been Rs 15750.
Let's calculate the cost price of each bike if the selling price is Rs 15750:
For the first bike, the selling price of Rs 15750 is 120% of the cost price. So:
120% of cost price = Rs 15750
Cost price = Rs 13125
For the second bike, the selling price of Rs 15750 is 80% of the cost price. So:
80% of cost price = Rs 15750
Cost price = Rs 19687.50
The total cost price of the two bikes is Rs 13125 + Rs 19687.50 = Rs 32812.50
The total selling price of the two bikes after the discount is Rs 15750 + Rs 15750 = Rs 31500
So, the dealer's profit/loss percentage is: (31500 - 32812.50)/32812.50 * 100% = -4%.
Therefore, the answer is (c) 10.24% loss.