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In case of type-1 system steady state acceleration is :
  • a)
    Unity
  • b)
    Infinity
  • c)
    Zero
  • d)
    10
Correct answer is option 'B'. Can you explain this answer?
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In case of type-1 system steady state acceleration is :a)Unityb)Infini...
Explanation: In case of type-1 system steady state acceleration is infinity as for the type less than 3 acceleration is not defined it is infinity.
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In case of type-1 system steady state acceleration is :a)Unityb)Infini...
Steady state acceleration in a type-1 system

In control systems, type-1 systems refer to those systems that have at least one integrator in their open-loop transfer function. These systems are characterized by having a steady-state error for a step input, but the error becomes zero for a ramp input.

Understanding steady state acceleration

Steady-state acceleration refers to the acceleration of a system after it has reached a stable operating condition. In other words, it is the acceleration of the system when all transient responses have decayed, and the system has settled into a steady state.

Analysis of a type-1 system

Type-1 systems have the transfer function of the form:

G(s) = K / (s * (s + a))

Where K is the gain of the system and 'a' is a constant related to the pole location of the system.

Determining steady state acceleration

To find the steady-state acceleration of a type-1 system, we need to analyze its open-loop transfer function. The steady-state acceleration can be obtained by taking the second derivative of the output of the system with respect to time.

In the given options, the correct answer is option 'B' - Infinity. This means that the steady-state acceleration of a type-1 system is infinite.

Explanation of the answer

The reason for the steady-state acceleration being infinite in a type-1 system can be understood by analyzing the transfer function. In a type-1 system, the denominator of the transfer function has a pole at the origin (s = 0).

When we take the second derivative of the output with respect to time, we are essentially multiplying the transfer function by s^2. Since the denominator has a pole at s = 0, multiplying by s^2 will result in a division by zero. This causes the steady-state acceleration to be infinite.

Conclusion

In conclusion, the steady-state acceleration in a type-1 system is infinite. This is because the denominator of the transfer function has a pole at the origin, leading to a division by zero when taking the second derivative of the output with respect to time.
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