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Temperature of one Mole of helium gas is increased by 1 degree , hence increase in internal energy?
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Temperature of one Mole of helium gas is increased by 1 degree , hence...
We can answer the question easily of we assume He gas to behave ideally. The internal energy of an ideal gas depends only upon temperature. The internal energy of one mole of an ideal gas at T K is given by (3/2)*RT. Hence for a rise in temperature by 1 C (= 1 K) , change in internal energy of 1 mol of gas,

∆E = (3/2)*R(T+1) -( 3/2)*RT = (3/2)R*1K

R= 8.314 J K^-1mol^-1

∆E = (3/2)*8.314 J mol^-1 = 12.471 J mol^-1
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Temperature of one Mole of helium gas is increased by 1 degree , hence...
**Increase in Temperature and Internal Energy of Helium Gas**

When the temperature of a gas is increased, its internal energy also increases. This is because temperature is a measure of the average kinetic energy of the gas particles, and an increase in temperature implies an increase in the kinetic energy of the gas particles.

**Internal Energy of a Gas**

The internal energy of a gas is the total energy associated with the random motion of its particles. It includes both the kinetic energy and the potential energy of the gas particles. The kinetic energy is due to the motion of the particles, while the potential energy is due to the intermolecular forces between the particles.

**Mole of Helium Gas**

A mole is a unit used to measure the amount of a substance and is defined as the amount of a substance that contains the same number of particles as there are atoms in exactly 12 grams of carbon-12.

One mole of helium gas contains Avogadro's number of helium atoms, which is approximately 6.022 × 10^23 atoms.

**Increase in Temperature and Kinetic Energy**

When the temperature of a gas is increased, the kinetic energy of the gas particles increases. This is because an increase in temperature corresponds to an increase in the average speed of the gas particles. The kinetic energy of a gas particle is given by the equation:

KE = (1/2)mv^2

Where:
- KE is the kinetic energy
- m is the mass of the gas particle
- v is the velocity of the gas particle

**Increase in Internal Energy**

As the temperature of the helium gas is increased by 1 degree, the average kinetic energy of the gas particles increases. This increase in kinetic energy leads to an increase in the internal energy of the gas.

The increase in internal energy can be calculated using the equation:

ΔU = (3/2)nRΔT

Where:
- ΔU is the change in internal energy
- n is the number of moles of gas
- R is the ideal gas constant
- ΔT is the change in temperature

Since we have one mole of helium gas, we can substitute n = 1 into the equation:

ΔU = (3/2)RΔT

Therefore, the increase in internal energy of one mole of helium gas when the temperature is increased by 1 degree is equal to (3/2)R times the change in temperature.

Note: The ideal gas constant, R, is a known constant with a value of 8.314 J/mol·K.
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Temperature of one Mole of helium gas is increased by 1 degree , hence increase in internal energy?
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